Find the upward velocity $V$ of load $m$ in the pulley system as shown in figure in which each cable at $A$ and $B$ is given velocity of $2m/\sec $ in the direction of the arrow.
(A) $1.5m/\sec $
(B) $3m/\sec $
(C) $6.3m/\sec $
(D) $4.5m/\sec $
Answer
606.6k+ views
Hint: Use the relation of constraint motion for pulley to find the expression for upward velocity $V$ of pulley and use the given velocity of cables in the expression of upward velocity.
Complete Step by Step Solution: -
According to the question, it is given that –
Let the velocity of each cables $A$ and $B$ be $v$ and let the upward velocity of mass $m$ be $V$
Therefore, velocity of each cable $A$ and $B$, $v = 2m/\sec $
For getting the answer the figure given in question can be drawn as –
Now, from the figure using the constraint relation of pulley, we get –
$
x = \dfrac{{v + 0}}{2} \\
\Rightarrow x = \dfrac{v}{2} \cdots \left( 1 \right) \\
$
Now, the value of $y$ from the figure can be given by –
$y = \dfrac{{v + x}}{2} \cdots \left( 2 \right)$
Using the value of $x$ from equation $\left( 1 \right)$ in equation $\left( 2 \right)$, we get –
$
y = \dfrac{{v + \dfrac{v}{2}}}{2} \\
\Rightarrow y = \dfrac{{2v + v}}{4} \\
\Rightarrow y = \dfrac{{3v}}{4} \\
$
Now, from the figure, we can conclude that $y$ is the velocity of mass $m$. So, the upward velocity is –
$V = \dfrac{{3v}}{4}$
Putting the value of $v$ in the above equation –
$
V = \dfrac{{3 \times 2}}{4} \\
\Rightarrow V = \dfrac{6}{4} \\
\Rightarrow V = \dfrac{3}{2}m/\sec \\
\Rightarrow V = 1.5m/\sec \\
$
Hence, the correct option is (A).
Note: - Constraint relation states that the sum of product of all tensions is strings and velocity of respective blocks connected with the string is equal to zero. We can also say that total power by the tension is zero. This can be represented mathematically by –
$\sum {T.} \bar v = 0$
The constraint relation works only when the strings are inextensible and taut.
When it is given that specific pulley is mass less than the tensions on both the sides of that pulley are equal.
Complete Step by Step Solution: -
According to the question, it is given that –
Let the velocity of each cables $A$ and $B$ be $v$ and let the upward velocity of mass $m$ be $V$
Therefore, velocity of each cable $A$ and $B$, $v = 2m/\sec $
For getting the answer the figure given in question can be drawn as –
Now, from the figure using the constraint relation of pulley, we get –
$
x = \dfrac{{v + 0}}{2} \\
\Rightarrow x = \dfrac{v}{2} \cdots \left( 1 \right) \\
$
Now, the value of $y$ from the figure can be given by –
$y = \dfrac{{v + x}}{2} \cdots \left( 2 \right)$
Using the value of $x$ from equation $\left( 1 \right)$ in equation $\left( 2 \right)$, we get –
$
y = \dfrac{{v + \dfrac{v}{2}}}{2} \\
\Rightarrow y = \dfrac{{2v + v}}{4} \\
\Rightarrow y = \dfrac{{3v}}{4} \\
$
Now, from the figure, we can conclude that $y$ is the velocity of mass $m$. So, the upward velocity is –
$V = \dfrac{{3v}}{4}$
Putting the value of $v$ in the above equation –
$
V = \dfrac{{3 \times 2}}{4} \\
\Rightarrow V = \dfrac{6}{4} \\
\Rightarrow V = \dfrac{3}{2}m/\sec \\
\Rightarrow V = 1.5m/\sec \\
$
Hence, the correct option is (A).
Note: - Constraint relation states that the sum of product of all tensions is strings and velocity of respective blocks connected with the string is equal to zero. We can also say that total power by the tension is zero. This can be represented mathematically by –
$\sum {T.} \bar v = 0$
The constraint relation works only when the strings are inextensible and taut.
When it is given that specific pulley is mass less than the tensions on both the sides of that pulley are equal.
Recently Updated Pages
Lysosomes are known as suicidal bags of cell why class 11 biology CBSE

Father s age is three times the sum of the ages of-class-11-maths-CBSE

Give a comparative account of the classes of kingdom class 11 biology CBSE

The ceiling of a long hall is 25m high What is the class 11 physics CBSE

Name the Largest and the Smallest Cell in the Human Body ?

Draw a welllabelled diagram of a plant cell class 11 biology CBSE

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

