
Find the total surface area of cube having length of the edge \[{\text{10cm}}\]
Answer
484.5k+ views
Hint: As we know that the area of one face of cube with side length a is \[{{\text{a}}^{\text{2}}}\]. And a cube is a combination of \[{\text{6}}\] face so total surface area is \[{\text{6}}{{\text{a}}^{\text{2}}}\].
Complete step-by-step answer:
As given that the length of the edge is \[{\text{10cm}}\].
And so the total surface area of cube is \[{\text{6}}{{\text{a}}^{\text{2}}}\]
\[
{\text{ = 6(10}}{{\text{)}}^{\text{2}}} \\
{\text{ = 6(100)}} \\
{\text{ = 600c}}{{\text{m}}^{\text{2}}} \\
\]
Hence 600 ${cm}^{2}$ is our required answer
Note: Cube is 3D shaped geometry, having 6 faces, 8 vertices and 12 edges.
Properties of Cube
1.It has all its faces in a square shape.
2.All the faces or sides have equal dimensions.
3.The plane angles of the cube are the right angle.
4.Each of the faces meets the other four faces.
5.Each of the vertices meets the three faces and three edges.
Complete step-by-step answer:

As given that the length of the edge is \[{\text{10cm}}\].
And so the total surface area of cube is \[{\text{6}}{{\text{a}}^{\text{2}}}\]
\[
{\text{ = 6(10}}{{\text{)}}^{\text{2}}} \\
{\text{ = 6(100)}} \\
{\text{ = 600c}}{{\text{m}}^{\text{2}}} \\
\]
Hence 600 ${cm}^{2}$ is our required answer
Note: Cube is 3D shaped geometry, having 6 faces, 8 vertices and 12 edges.
Properties of Cube
1.It has all its faces in a square shape.
2.All the faces or sides have equal dimensions.
3.The plane angles of the cube are the right angle.
4.Each of the faces meets the other four faces.
5.Each of the vertices meets the three faces and three edges.
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