Find the tension in the string.
Answer
531k+ views
Hint: Tension is nothing but the force that acts in an axial direction. we know that the tensile force and compressive force. The tensile force means the stretching force acting on the material. The object is hung by ropes, strings, and chains, the tensile force acts in an axial direction in the ropes or strings due to the mass of the object. The tensions are to be measured here in the problem.
Formula used:
For the object, which is hung by the string and is in stationary (not moving)
The tension in the string $T = W$, $\left( {W = m \times g} \right)$
$T = m \times g$
Where T- the tension in the string
$W$- weight of the object hung by the string (N)
\[m\] - the mass of the object hung by the string
\[g\] - acceleration due to gravity $\left( {g = 9.81 \times \dfrac{m}{{{s^2}}}} \right)$
Complete answer:
We are going to find the tensions of the string $T_1,T_2$.
To find the tension $T_1$,${m_1} = 2kg$
$T_1 = {m_1} \times g$
$T_1 = 2 \times 9.81$
$T_1 = 19.62N$
The tension of the string $T_1 = 19.62N$
To find the tension $T_2,{m_2} = 5kg$
$T_2 = {m_2} \times g$
$T_2 = 5 \times 9.81$
$T_2 = 49.05N$
The tension of the string $T_2 = 49.05N$
From the above calculations, we found that the tensions of the string as a result.
$T_1 = 19.62N$,$T_2 = 49.05N$
Note: For example, if we stretch the rubber bands, it undergoes tensile force and causes tension in the rubber band. The tensile strength of the material is defined as the ability of the material by which it can sustain the maximum amount of load when being stretched. These calculations can be used in constructions and manufacturing industrial components, The tension of the string, rope, or chain during acceleration is $T = W \pm m.a$. For the object goes upward,$T = W + m.a$and for the object goes downward, $T = W - m.a$.
Formula used:
For the object, which is hung by the string and is in stationary (not moving)
The tension in the string $T = W$, $\left( {W = m \times g} \right)$
$T = m \times g$
Where T- the tension in the string
$W$- weight of the object hung by the string (N)
\[m\] - the mass of the object hung by the string
\[g\] - acceleration due to gravity $\left( {g = 9.81 \times \dfrac{m}{{{s^2}}}} \right)$
Complete answer:
We are going to find the tensions of the string $T_1,T_2$.
To find the tension $T_1$,${m_1} = 2kg$
$T_1 = {m_1} \times g$
$T_1 = 2 \times 9.81$
$T_1 = 19.62N$
The tension of the string $T_1 = 19.62N$
To find the tension $T_2,{m_2} = 5kg$
$T_2 = {m_2} \times g$
$T_2 = 5 \times 9.81$
$T_2 = 49.05N$
The tension of the string $T_2 = 49.05N$
From the above calculations, we found that the tensions of the string as a result.
$T_1 = 19.62N$,$T_2 = 49.05N$
Note: For example, if we stretch the rubber bands, it undergoes tensile force and causes tension in the rubber band. The tensile strength of the material is defined as the ability of the material by which it can sustain the maximum amount of load when being stretched. These calculations can be used in constructions and manufacturing industrial components, The tension of the string, rope, or chain during acceleration is $T = W \pm m.a$. For the object goes upward,$T = W + m.a$and for the object goes downward, $T = W - m.a$.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

