
Find the sum of the product of x(x + y – r), y(x – y + r) and z(x – y – z)
Answer
519.6k+ views
Hint: Find the product of each of the three terms separately. Then add up these three quantities and write the sum.
Complete step-by-step answer:
The three quantities are given in terms of factors. First, we need to find the products of the factors for these three terms separately.
i) $\text{x}\left( \text{x + y }-\text{ r} \right)\text{ = }{{\text{x}}^{2}}\text{ + xy }-\text{ xr}$
ii) $\text{y}\left( \text{x }-\text{ y + r} \right)\ \text{= xy }-\text{ }{{\text{y}}^{2}}\text{ + yr}$
iii) $\text{z}\left( \text{x }-\text{ y }-\text{ z} \right)\text{ = xz }-\text{ yz }-\text{
}{{\text{z}}^{2}}$
Now, that the products of the three quantities are obtained, their sum is –
$\begin{align}
& \left( {{\text{x}}^{2}}\text{ + xy }-\text{ xr} \right)\text{ + }\left( \text{xy }-\text{ }{{\text{y}}^{2}}\text{ + yr} \right)\text{ + }\left( \text{xz }-\text{ yz }-\text{ }{{\text{z}}^{2}} \right) \\
& =\text{ }{{\text{x}}^{2}}\text{ }-\text{ }{{\text{y}}^{2}}\text{ }-\text{ }{{\text{z}}^{2}}\text{ + 2xy +xz }-\text{ xr + yr }-\text{ yz} \\
\end{align}$
Thus, the sum of the three quantities given in the question is $\text{ }{{\text{x}}^{2}}\text{ }-\text{ }{{\text{y}}^{2}}\text{ }-\text{ }{{\text{z}}^{2}}\text{ + 2xy +xz }-\text{ xr + yr }-\text{ yz}$.
Note: This solution can be done alternatively without finding the products alternatively. Instead, one can directly add the three quantities and then find the product of the quantities under the summation itself. By both the methods, the final summation of the products comes to be the same answer.
Complete step-by-step answer:
The three quantities are given in terms of factors. First, we need to find the products of the factors for these three terms separately.
i) $\text{x}\left( \text{x + y }-\text{ r} \right)\text{ = }{{\text{x}}^{2}}\text{ + xy }-\text{ xr}$
ii) $\text{y}\left( \text{x }-\text{ y + r} \right)\ \text{= xy }-\text{ }{{\text{y}}^{2}}\text{ + yr}$
iii) $\text{z}\left( \text{x }-\text{ y }-\text{ z} \right)\text{ = xz }-\text{ yz }-\text{
}{{\text{z}}^{2}}$
Now, that the products of the three quantities are obtained, their sum is –
$\begin{align}
& \left( {{\text{x}}^{2}}\text{ + xy }-\text{ xr} \right)\text{ + }\left( \text{xy }-\text{ }{{\text{y}}^{2}}\text{ + yr} \right)\text{ + }\left( \text{xz }-\text{ yz }-\text{ }{{\text{z}}^{2}} \right) \\
& =\text{ }{{\text{x}}^{2}}\text{ }-\text{ }{{\text{y}}^{2}}\text{ }-\text{ }{{\text{z}}^{2}}\text{ + 2xy +xz }-\text{ xr + yr }-\text{ yz} \\
\end{align}$
Thus, the sum of the three quantities given in the question is $\text{ }{{\text{x}}^{2}}\text{ }-\text{ }{{\text{y}}^{2}}\text{ }-\text{ }{{\text{z}}^{2}}\text{ + 2xy +xz }-\text{ xr + yr }-\text{ yz}$.
Note: This solution can be done alternatively without finding the products alternatively. Instead, one can directly add the three quantities and then find the product of the quantities under the summation itself. By both the methods, the final summation of the products comes to be the same answer.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Trending doubts
A number is chosen from 1 to 20 Find the probabili-class-10-maths-CBSE

Find the area of the minor segment of a circle of radius class 10 maths CBSE

Distinguish between the reserved forests and protected class 10 biology CBSE

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

A gulab jamun contains sugar syrup up to about 30 of class 10 maths CBSE

Leap year has days A 365 B 366 C 367 D 368 class 10 maths CBSE
