Find the sum of the following arithmetic progression.
$50, 46, 42,....$ to $10$ terms.
Answer
582.9k+ views
Hint:
Here, they have given an arithmetic series and they are asking to find the arithmetic progression. So, we have a formula to find the sum of $n$ terms of an arithmetic progression that is given by: ${S_n} = \dfrac{n}{2}[2a + (n - 1)d]$. By using this formula we can get the required answer.
Complete Step by Step Solution:
In the given problem they have given an arithmetic progression, and asking us to find sum of the arithmetic progression.
In order to find the sum of $n$ terms of an arithmetic progression we have a formula, given by
${S_n} = \dfrac{n}{2}[2a + (n - 1)d]$
Where ${S_n}$ is the sum of $n$ terms.
$n = $ number of terms.
$a = $ first term of the given arithmetic progression.
$d = $ common difference of the arithmetic progression.
The series is given by $50,46,42,....$ to $10$ terms.
From the given arithmetic progression, we can say that
Number of terms $n = 10$
The first term of the given arithmetic progression i.e., $a = 50$
Now, to find the common difference that is $d$, we follow the following procedure or formula
$d = {a_2} - {a_1}$Here, ${a_1} = 50$ and ${a_2} = 46$, by substituting these values, we get
$d = 45 - 50 = - 4$
Now, by substituting the values of $a,d$ and $n$in the sum of $n$ terms of an arithmetic progression formula, we get
${S_{10}} = \dfrac{{10}}{2}[2(50) + (10 - 1)( - 4)]$
On simplifying the above equation,
$ \Rightarrow {S_{10}} = (5)[100 + (9)( - 4)]$
$ \Rightarrow {S_{10}} = (5)[100 - 36]$
$ \Rightarrow {S_{10}} = (5)[64]$
$ \Rightarrow {S_{10}} = 320$
Therefore the sum of the arithmetic progression that is $50,46,42,....$ to $10$ terms is $320$.
Note:
If you want to cross verify the answer, or if you are not able to recall the formula then we can find the entire series, that is from the given expression $50,46,42,....$ to $10$ terms, we can notice that there is a difference of $4$for every number so by using this difference first try to find the entire series then by adding these we can get the answer to cross verify.
Here, they have given an arithmetic series and they are asking to find the arithmetic progression. So, we have a formula to find the sum of $n$ terms of an arithmetic progression that is given by: ${S_n} = \dfrac{n}{2}[2a + (n - 1)d]$. By using this formula we can get the required answer.
Complete Step by Step Solution:
In the given problem they have given an arithmetic progression, and asking us to find sum of the arithmetic progression.
In order to find the sum of $n$ terms of an arithmetic progression we have a formula, given by
${S_n} = \dfrac{n}{2}[2a + (n - 1)d]$
Where ${S_n}$ is the sum of $n$ terms.
$n = $ number of terms.
$a = $ first term of the given arithmetic progression.
$d = $ common difference of the arithmetic progression.
The series is given by $50,46,42,....$ to $10$ terms.
From the given arithmetic progression, we can say that
Number of terms $n = 10$
The first term of the given arithmetic progression i.e., $a = 50$
Now, to find the common difference that is $d$, we follow the following procedure or formula
$d = {a_2} - {a_1}$Here, ${a_1} = 50$ and ${a_2} = 46$, by substituting these values, we get
$d = 45 - 50 = - 4$
Now, by substituting the values of $a,d$ and $n$in the sum of $n$ terms of an arithmetic progression formula, we get
${S_{10}} = \dfrac{{10}}{2}[2(50) + (10 - 1)( - 4)]$
On simplifying the above equation,
$ \Rightarrow {S_{10}} = (5)[100 + (9)( - 4)]$
$ \Rightarrow {S_{10}} = (5)[100 - 36]$
$ \Rightarrow {S_{10}} = (5)[64]$
$ \Rightarrow {S_{10}} = 320$
Therefore the sum of the arithmetic progression that is $50,46,42,....$ to $10$ terms is $320$.
Note:
If you want to cross verify the answer, or if you are not able to recall the formula then we can find the entire series, that is from the given expression $50,46,42,....$ to $10$ terms, we can notice that there is a difference of $4$for every number so by using this difference first try to find the entire series then by adding these we can get the answer to cross verify.
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