Question

Find the sum of interior angles of a polygon with: 9 sides.

Answer 1

Hint: In order to solve this question, to find the sum of interior angles of a polygon with the given number of sides, we will apply the formula to find the sum of interior angles of any type of polygon i.e.. $(2n - 4) \times {90^\circ }$.

Complete step-by-step solution:
If the given polygon have 9sides, then-
Number of sides, $n = 9$
Now, we will apply the formula to find the sum of interior angles of a polygon, if the number of sides is given.
So,
The sum of interior angles of polygon $ = (2n - 4) \times {90^\circ }$
$\Rightarrow (2 \times 9 - 4) \times {90^\circ } $
$ \Rightarrow (18 - 4) \times {90^\circ }$
$\Rightarrow 14 \times {90^\circ } $
we get,
$ \Rightarrow {1260^\circ }$
Hence, the sum of the interior angles of a polygon with 9 sides is ${1260^\circ }$.

Note: The term "concave polygon" refers to a polygon with at least one angle greater than ${180^\circ }$ . This polygon's vertices (endpoints) are both inwards and outwards. They are diametrically opposed to convex polygons.