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Find the sum: $ \dfrac{2}{9} + \dfrac{5}{6} $

Answer
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Hint: As we can see that in the above questions we have fractions and we have to find the sum of the given expression. We can see that both of the fractions are unlike fractions so we have to find the LCM of the denominators and then we add them accordingly to their numerators.

Complete step-by-step answer:
Here we have to add $ \dfrac{2}{9} + \dfrac{5}{6} $
We have the LCM of $ 9,6 $ and it is $ 18 $ . So now we can convert the fractions with the same denominator .
The first fraction can be written as $ \dfrac{{2 \times 2}}{{9 \times 2}} = \dfrac{4}{{18}} $ and the second fraction can be written as $ \dfrac{{5 \times 3}}{{6 \times 3}} = \dfrac{{15}}{{18}} $
We will add the fractions now i.e.
 $ \dfrac{4}{{18}} + \dfrac{{15}}{{18}} = \dfrac{{4 + 15}}{{18}} = \dfrac{{19}}{{18}} $ .
Hence the required answer is $ \dfrac{{19}}{{18}} $ .
So, the correct answer is “ $ \dfrac{{19}}{{18}} $ ”.

Note: We should note that the factors of $ 9 $ is $ 3 \times 3 $ and the factors of $ 6 = 2 \times 3 $ , so from this we get our least common multiple or LCM $ = 3 \times 3 \times 2 = 18 $ . We should always try to convert the unlike fractions into like fractions and then solve them. We can also add both the fractions i.e. $ \dfrac{2}{9} + \dfrac{5}{6} = \dfrac{{2 \times 2 + 5 \times 3}}{{18}} $ . It gives us the same value $ \dfrac{{19}}{{18}} $ .