Answer

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Hint: To solve this problem we should know about Vedic maths because the method Viloknanam which is Vedic math concept. This method is used to find the square root of 3 or 4 digit perfect square numbers.

Complete step-by-step answer:

Here we are finding the square root of 9604 using Vilokanam methods

Now we solve the problem in a step by step process.

Let us consider the unit digit. In this number unit digit is 4

Then we have to find the unit digit of square root

Therefore we know that the unit digit of square root is 2 or 8.

Now let us ignore the last two digits (unit digit and ten digit)

On ignoring the unit digit and tens digit we get the number as 96.

Later we have found the greatest number whose square is less than or equal to the remaining part of the number.

Here the greatest number whose square root is less than or equal to 96 is 9.

Now we have to adjust the obtained unit digit 2 or 8 to the number 96 then we get 92 or 98.

Then we have to find out the unique number with unit digit number 5 that lies between 92 and 98 is 95.

Here the ${(95)^2} = 9025$

Since 9604 >9025 the required square root is 98.

Thus $\sqrt {9604} = 98$

Option A is the correct answer.

Note: The method mentioned in the problem belongs to Vedic math, since it belongs to Vedic math we have to follow the given step without any addition of extra point’s .Here we have to follow the above steps to solve the problem in Vilokanam method. We have to make a note that in the last step after finding the square root of the number the number should be less than or equal to the given number if not we have to check for another number as the square root of the number should be less than or equal to the given number.

Complete step-by-step answer:

Here we are finding the square root of 9604 using Vilokanam methods

Now we solve the problem in a step by step process.

Let us consider the unit digit. In this number unit digit is 4

Then we have to find the unit digit of square root

Therefore we know that the unit digit of square root is 2 or 8.

Now let us ignore the last two digits (unit digit and ten digit)

On ignoring the unit digit and tens digit we get the number as 96.

Later we have found the greatest number whose square is less than or equal to the remaining part of the number.

Here the greatest number whose square root is less than or equal to 96 is 9.

Now we have to adjust the obtained unit digit 2 or 8 to the number 96 then we get 92 or 98.

Then we have to find out the unique number with unit digit number 5 that lies between 92 and 98 is 95.

Here the ${(95)^2} = 9025$

Since 9604 >9025 the required square root is 98.

Thus $\sqrt {9604} = 98$

Option A is the correct answer.

Note: The method mentioned in the problem belongs to Vedic math, since it belongs to Vedic math we have to follow the given step without any addition of extra point’s .Here we have to follow the above steps to solve the problem in Vilokanam method. We have to make a note that in the last step after finding the square root of the number the number should be less than or equal to the given number if not we have to check for another number as the square root of the number should be less than or equal to the given number.

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