
How do you find the square root of $6561$?
Answer
544.5k+ views
Hint:In order to determine the square root of the number $6561$, first we have to find the factors of number $6561$ and choose the largest factor which is a perfect square. You will get that our number is a perfect square .Now writing the prime factors of $6561$you will get a answer of ${3^8}$and after putting this from the square root you will get an answer of ${3^4} = 81$.
Complete step by step solution:
We a given a number $6561$
Square root of any number is actually a number whose square gives back the original number.
So, square root of $6561$can be written as,
$ = \sqrt {6561} $
Now , we’ll Separating the value $6561$ into its factors, So the factors of $6561$ comes to be,
$1,3,9,27,81,243,729,2187,6561$
Now let’s find the factors who are perfect squares of any number, we got
$1,9,81,729,6561$
So if see the largest number from above we found that it is the original number
If we find the prime factors of $6561$
We’ll get $6561 = 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3$
From the above we can say that $6561 = {3^8}$
Replace $6561$as ${3^8}$ in the original number
$
= \sqrt {6561} \\
= \sqrt {{3^8}} \\
= {3^4} \\
= 81 \\
$
Therefore, the square root of $\sqrt {6561} $in the simplest form is equal to $81$.
Additional Information:
A Perfect square is a number which can be easily expressed in terms of square of any number .
For example,$16$is a perfect square of number $4$as${4^2} = 16$.
Note: 1. Don’t Forgot to cross check the answer.
2.Factorise the number inside the square root properly to get knowledge of every perfect square.
3.Do the prime factorization carefully.
Complete step by step solution:
We a given a number $6561$
Square root of any number is actually a number whose square gives back the original number.
So, square root of $6561$can be written as,
$ = \sqrt {6561} $
Now , we’ll Separating the value $6561$ into its factors, So the factors of $6561$ comes to be,
$1,3,9,27,81,243,729,2187,6561$
Now let’s find the factors who are perfect squares of any number, we got
$1,9,81,729,6561$
So if see the largest number from above we found that it is the original number
If we find the prime factors of $6561$
We’ll get $6561 = 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3$
From the above we can say that $6561 = {3^8}$
Replace $6561$as ${3^8}$ in the original number
$
= \sqrt {6561} \\
= \sqrt {{3^8}} \\
= {3^4} \\
= 81 \\
$
Therefore, the square root of $\sqrt {6561} $in the simplest form is equal to $81$.
Additional Information:
A Perfect square is a number which can be easily expressed in terms of square of any number .
For example,$16$is a perfect square of number $4$as${4^2} = 16$.
Note: 1. Don’t Forgot to cross check the answer.
2.Factorise the number inside the square root properly to get knowledge of every perfect square.
3.Do the prime factorization carefully.
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