Answer
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Hint: In order to find the square of any number we just need to multiply the given number by itself once to get the desired answer.
\[{a^2} = a \times a\] where a is a real number.
Complete step-by-step answer:
Here the given number is 31.
Let \[x = 31\]
Now as we know that in order to find the square of any number we just need to multiply the given number by itself once.
Therefore we have to multiply x by itself once to get its square.
Hence on multiplying we get:-
\[{x^2} = x \times x\]
Now putting in the value of x we get:-
\[{\left( {31} \right)^2} = 31 \times 31\]
Evaluating the right hand side further we get:-
\[ \Rightarrow {\left( {31} \right)^2} = 961\]
Hence the square of 31 is 961.
Note: Students should take a note that they can find the square of any real number.
Also they have to multiply the number by itself only once in order to get its square.
When a number in square root is multiplied by itself then it gives the number under the square root as the result.
\[
{\left( {\sqrt a } \right)^2} = \sqrt a \times \sqrt a \\
{\text{ }} = a \\
\]
\[{a^2} = a \times a\] where a is a real number.
Complete step-by-step answer:
Here the given number is 31.
Let \[x = 31\]
Now as we know that in order to find the square of any number we just need to multiply the given number by itself once.
Therefore we have to multiply x by itself once to get its square.
Hence on multiplying we get:-
\[{x^2} = x \times x\]
Now putting in the value of x we get:-
\[{\left( {31} \right)^2} = 31 \times 31\]
Evaluating the right hand side further we get:-
\[ \Rightarrow {\left( {31} \right)^2} = 961\]
Hence the square of 31 is 961.
Note: Students should take a note that they can find the square of any real number.
Also they have to multiply the number by itself only once in order to get its square.
When a number in square root is multiplied by itself then it gives the number under the square root as the result.
\[
{\left( {\sqrt a } \right)^2} = \sqrt a \times \sqrt a \\
{\text{ }} = a \\
\]
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