Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

Find the slope of the line joining the points$( - 4,1)$and$( - 5,2)$

Answer
VerifiedVerified
579.9k+ views
Hint: Let$M({x_1},{y_1}) = ( - 4,1)$and$N({x_2},{y_2}) = ( - 5,2)$Verify that ${x_1} \ne {x_2}$
Then use the formula $m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}$to determine the required slope.

Complete step by step solution:
In this problem, we are given two points but not the equation of the line joining them.
Determining the slope of a line from its equation is an easy task.
However, it is not difficult to determine the slope in this case either.
Let$M({x_1},{y_1})$and$N({x_2},{y_2})$be two points on a plane. The slope of a line joining the two
points M and N is denoted by m and is given by the formula: slope$ = m = \dfrac{{{y_2} - {y_1}}}{{{x_2} -
{x_1}}}$where the x-coordinates ${x_1} \ne {x_2}$
We can see that if${x_1} = {x_2}$, then the denominator in the formula would be equal to zero and the
slope would be not defined.
A graphical representation of the slope of a line joining the points M and N would be as given below:
seo images


We are given two points $( - 4,1)$and$( - 5,2)$
We need to find the slope of the line joining these two points.
From the above discussion, it is clear that we need to check if the slope is defined in order to apply the
formula for calculating the slope.
Let$M({x_1},{y_1}) = ( - 4,1)$and$N({x_2},{y_2}) = ( - 5,2)$
Therefore, the x-coordinates of M and N are -4 and -5 which are clearly different from each other.
This implies that we can use the formula of slope given above.
So, let us substitute the values in the formula.
Therefore, we have slope\[ = m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \dfrac{{2 - 1}}{{ - 5 - ( - 4)}} =
\dfrac{1}{{ - 5 + 4}} = \dfrac{1}{{ - 1}} = - 1\]
Hence the slope of the line joining the points $( - 4,1)$and$( - 5,2)$is -1.
Note: Slope of a line is constant throughout the way.
That is, for any two points on a given line, the value of m remains constant.