
How do you find the slope it exists $ y=-7+4 $?
Answer
557.7k+ views
Hint: The only case where the slope of any straight line does not exist is if the straight line is parallel to the Y-axis in that case the slope will tend to infinity. The equation of the straight line is x is constant. In all other cases, we can find the slope by writing the equation in the form of $ y=mx+c $
Complete step by step answer:
The given equation of a straight line in the question is $ y=-7+4 $
We can solve further and write y=-3
In this equation y is a constant, the straight line y=-3 will never touch the X-axis it is parallel to X-axis
We can write y=-3 in the form of $ y=mx+c $
So $ y=0\times x+\left( -3 \right) $
So we can see in the place of m, 0 is there. So the slope of straight line y=-3 is equal to 0
We can draw the graph of y=-3
We can see that the line y=-3 is parallel to the X-axis and the slope of y=-3 is equal to 0.
Note:
Any line which is parallel to the X-axis has a slope of 0, the equation of such line is y equals a constant. Any line which is parallel to the Y-axis has the slope tend to infinity, so the slope of the line does not exist. The equation such line is x equals a constant.
Complete step by step answer:
The given equation of a straight line in the question is $ y=-7+4 $
We can solve further and write y=-3
In this equation y is a constant, the straight line y=-3 will never touch the X-axis it is parallel to X-axis
We can write y=-3 in the form of $ y=mx+c $
So $ y=0\times x+\left( -3 \right) $
So we can see in the place of m, 0 is there. So the slope of straight line y=-3 is equal to 0
We can draw the graph of y=-3
We can see that the line y=-3 is parallel to the X-axis and the slope of y=-3 is equal to 0.
Note:
Any line which is parallel to the X-axis has a slope of 0, the equation of such line is y equals a constant. Any line which is parallel to the Y-axis has the slope tend to infinity, so the slope of the line does not exist. The equation such line is x equals a constant.
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