
How do you find the slope and intercept of $y=-\dfrac{3}{5}x+2$?
Answer
545.7k+ views
Hint: In this problem we need to calculate the slope and intercept of the given linear equation. For this we are going to find any two points on the given line. So, we will assume various values of the $x$ and substitute them in the given equation of the line and calculate the value of $y$. From those values we can write the points on the line as $\left( x,y \right)$. Here we need to calculate the slope of the equation which can be written as $\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}$ where $\left( {{x}_{1}},{{y}_{1}} \right)$, $\left( {{x}_{2}},{{y}_{2}} \right)$ are the two points on the line. to calculate the intercept of the given equation we will calculate the value of $y$ at $x=0$.
Complete step by step solution:
The equation of the line is $y=-\dfrac{3}{5}x+2$.
Let us calculate the value of $y$ at $x=0$ by substituting the value of $x$ in the given line equation, then we will get
$\begin{align}
& \Rightarrow y=-\dfrac{3}{5}\left( 0 \right)+2 \\
& \Rightarrow y=2 \\
\end{align}$
Hence the point on the line is $\left( 0,2 \right)$.
Let us again calculate the value of $y$ at $x=1$ by substituting the value of $x$ in the given line equation, then we will get
$\begin{align}
& \Rightarrow y=-\dfrac{3}{5}\left( 1 \right)+2 \\
& \Rightarrow y=-\dfrac{3}{5}+2 \\
& \Rightarrow y=\dfrac{-3+10}{5} \\
& \Rightarrow y=\dfrac{7}{5} \\
\end{align}$
Hence the point on the line is $\left( 1,\dfrac{7}{5} \right)$.
Now the slope of the given line which passes through $\left( 0,2 \right)$, $\left( 1,\dfrac{7}{5} \right)$ will be
$\begin{align}
& \Rightarrow m=\dfrac{\dfrac{7}{5}-2}{1-0} \\
& \Rightarrow m=\dfrac{7-10}{5} \\
& \Rightarrow m=-\dfrac{3}{5} \\
\end{align}$
Now the value of $y$ at $x=0$ is $2$.
Hence the slope of the given line is $-\dfrac{3}{5}$, intercept is $2$ and the graph of the given line will be
Note: From the given equation also, we can calculate the required data. If we observe the equation it is in slope intercept form so we can compare the given equation with $y=mx+c$ and write the values of slope $\left( m \right)$ and intercept $\left( c \right)$.
Complete step by step solution:
The equation of the line is $y=-\dfrac{3}{5}x+2$.
Let us calculate the value of $y$ at $x=0$ by substituting the value of $x$ in the given line equation, then we will get
$\begin{align}
& \Rightarrow y=-\dfrac{3}{5}\left( 0 \right)+2 \\
& \Rightarrow y=2 \\
\end{align}$
Hence the point on the line is $\left( 0,2 \right)$.
Let us again calculate the value of $y$ at $x=1$ by substituting the value of $x$ in the given line equation, then we will get
$\begin{align}
& \Rightarrow y=-\dfrac{3}{5}\left( 1 \right)+2 \\
& \Rightarrow y=-\dfrac{3}{5}+2 \\
& \Rightarrow y=\dfrac{-3+10}{5} \\
& \Rightarrow y=\dfrac{7}{5} \\
\end{align}$
Hence the point on the line is $\left( 1,\dfrac{7}{5} \right)$.
Now the slope of the given line which passes through $\left( 0,2 \right)$, $\left( 1,\dfrac{7}{5} \right)$ will be
$\begin{align}
& \Rightarrow m=\dfrac{\dfrac{7}{5}-2}{1-0} \\
& \Rightarrow m=\dfrac{7-10}{5} \\
& \Rightarrow m=-\dfrac{3}{5} \\
\end{align}$
Now the value of $y$ at $x=0$ is $2$.
Hence the slope of the given line is $-\dfrac{3}{5}$, intercept is $2$ and the graph of the given line will be
Note: From the given equation also, we can calculate the required data. If we observe the equation it is in slope intercept form so we can compare the given equation with $y=mx+c$ and write the values of slope $\left( m \right)$ and intercept $\left( c \right)$.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

