Question

How do you find the slope and intercept of \[x + 1 = 0\]?

Answer 1

Hint: Using the equation of line, we find the slope of the line. Comparing the equation of a given line to the general equation of line we write the value of slope.
* General equation of the line is \[y = mx + c\] where m is the slope of the line.
* Intercept means the point where the line crosses the respective axis.

Complete step-by-step solution:
We have the equation of line \[x + 1 = 0\].
SLOPE OF EQUATION:
We can see this equation has no value of y in the equation, so the equation cannot be written in the form of general equation of line i.e. \[y = mx + c\].
Since we cannot write \[x + 1 = 0\] in the general form of the equation of line, there is no slope for this line.
INTERCEPT OF LINE:
Since we know that x-intercept means the point on x-axis where the line cuts the axis and y-intercept means the point on y-axis where the line cuts the y-axis, we will equate the equation of line to 0 and calculate the values of intercepts.
Since the equation \[x + 1 = 0\] does not have y in the equation, there is no y-intercept for this equation?
If we equate the equation to 0 we get \[x + 1 = 0\]
Shift constant values to right side of the equation
\[ \Rightarrow x = - 1\]
So, we get the value of x as -1
So, the value of x-intercept is -1

\[\therefore \]\[x + 1 = 0\] has no slope and has x-intercept as -1.

Note: Students are likely to make mistakes while shifting the values from one side of the equation to another side of the equation as they forget to change the sign of the value shifted. Keep in mind we always change the sign of the value from positive to negative and vice versa when shifting values from one side of the equation to another side of the equation.
Also, many students write the slope of equation as 1 as they think y-coordinate is 0 and they compare the equation with the general equation which is wrong.