
Find the size, nature and position of the image formed when an object of size is placed at a distance of from a concave mirror of focal length .
Answer
500.1k+ views
Hint: Use the mirror equation to derive the position of image. Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height.
Formula Used:
The mirror equation
Where is the image distance, is the object distance and is the focal length.
Also the magnification of mirrors is given by
Where is the image distance, is the object distance and is the focal length, is the magnification, is the height of the image and is the height of object.
Complete step by step answer:
Given,
{Using Sign Convention}
{Using sign convention since focal length of concave mirror is negative}
We can calculate by using the following equation,
Substituting the values of and in the above equation we get,
Taking L.C.M,
Taking the reciprocal, we get
Thus the image is formed in front of the mirror.
Now using the equation,
We substitute the values here,
On solving we get,
Thus the image is twice the size of object.
On solving further we get that,
The negative sign indicates that the image is virtual and inverted. This is also because the image is formed at the same side of the mirror with the object.
Hence finally, , and the image is real and inverted.
Note: Do not confuse the mirror formula with the lens formula and write the magnification formula correctly. Also do not forget to use sign convention correctly as it will cause an error in the answer. Take care of the negative sign in the image height.
Formula Used:
The mirror equation
Where
Also the magnification of mirrors is given by
Where
Complete step by step answer:
Given,
Substituting the values of
Taking L.C.M,
Taking the reciprocal, we get
Thus the image is formed
Now using the equation,
We substitute the values here,
On solving we get,
Thus the image is twice the size of object.
On solving further we get that,
The negative sign indicates that the image is virtual and inverted. This is also because the image is formed at the same side of the mirror with the object.
Hence finally,
Note: Do not confuse the mirror formula with the lens formula and write the magnification formula correctly. Also do not forget to use sign convention correctly as it will cause an error in the answer. Take care of the negative sign in the image height.
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