
Find the relation between a side and the circumradius of an equilateral triangle.
Answer
543.3k+ views
Hint: An equilateral triangle is a triangle that has all its sides equal in length. Also, the three angles of the equilateral triangle are congruent and equal to 60 degrees and circumradius is defined as the radius of that circle which surrounds the triangle and hence, we can find the relation between a side and circumradius by considering its interior angle.
Complete step by step solution:
As given we need to find the relation between a side and the circumradius of an equilateral triangle.
For a triangle,
\[\dfrac{a}{{\operatorname{Sin} A}} = 2R\]
In which R is the circumradius.
Here, \[A = 60^\circ \] ;
Since it is an Equilateral triangle, its interior angle is equal to 60 degrees, hence we need to find sin 60 degrees i.e.,
\[\dfrac{a}{{\sin A}} = 2R\]
\[\dfrac{a}{{\sin \left( {{{60}^\circ }} \right)}} = 2R\]
We know that, \[\sin {60^\circ } = \dfrac{{\sqrt 3 }}{2}\]
\[\dfrac{a}{{\dfrac{{\sqrt 3 }}{2}}} = 2R\]
\[a = \dfrac{{\sqrt 3 }}{2}\left( 2 \right)R\]
\[a = \sqrt 3 R\]
Therefore, the size of the equilateral triangle is \[\sqrt 3 \] of the circumradius.
Note: The key point to find an equilateral triangle is that we know that all three sides have the same length. In the familiar Euclidean geometry, an equilateral triangle is also equiangular; that is, all three internal angles are also congruent to each other and are each 60°, hence we need to consider its interior angle of the equilateral triangle to find the relation.
Complete step by step solution:
As given we need to find the relation between a side and the circumradius of an equilateral triangle.
For a triangle,
\[\dfrac{a}{{\operatorname{Sin} A}} = 2R\]
In which R is the circumradius.
Here, \[A = 60^\circ \] ;
Since it is an Equilateral triangle, its interior angle is equal to 60 degrees, hence we need to find sin 60 degrees i.e.,
\[\dfrac{a}{{\sin A}} = 2R\]
\[\dfrac{a}{{\sin \left( {{{60}^\circ }} \right)}} = 2R\]
We know that, \[\sin {60^\circ } = \dfrac{{\sqrt 3 }}{2}\]
\[\dfrac{a}{{\dfrac{{\sqrt 3 }}{2}}} = 2R\]
\[a = \dfrac{{\sqrt 3 }}{2}\left( 2 \right)R\]
\[a = \sqrt 3 R\]
Therefore, the size of the equilateral triangle is \[\sqrt 3 \] of the circumradius.
Note: The key point to find an equilateral triangle is that we know that all three sides have the same length. In the familiar Euclidean geometry, an equilateral triangle is also equiangular; that is, all three internal angles are also congruent to each other and are each 60°, hence we need to consider its interior angle of the equilateral triangle to find the relation.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

