
How do I find the real zeros of a function?
Answer
540.9k+ views
Hint: In the given question, we have been asked to find the real zeros of any function. This is equivalent to saying that we have to factorize the given quadratic equation. To do that, we can easily solve it by using the formula of calculating the value of the variable by using the concept of determinants. We use the formula for solving the value of determinants. Then we just put the value of the determinant into the formula for finding the variable, and that gives us the answer. But it is a point to note that if the value of the determinant is less than 0, i.e., negative, then there is no possible solution for the given equation.
Formula Used:
We are going to use the formula of calculating the value of the variable by using Determinant:
Determinant, \[D = {b^2} - 4ac\]
and, \[x = \dfrac{{ - b \pm \sqrt D }}{{2a}}\].
Complete step by step answer:
Say, we have to factorize a quadratic equation \[a{x^2} + bx + c\].
The formula for finding determinant is:
\[D = {b^2} - 4ac\]
Now, we put in the value of the determinant into the formula of finding the value of \[x\],
\[x = \dfrac{{ - b \pm \sqrt D }}{{2a}}\]
Then we just simplify and find the value of the roots.
Note: In the given question, we needed to factorize the given polynomial. It is not true that whenever there is a given problem, there will be a solution. So, first, we need to check if there are any solutions that can be possible. If there is, then only we proceed to calculate the solution. There is no point in calculating the solution when there is not any. For instance, there is no solution to the point of intersection of two parallel lines. Two parallel lines never intersect, hence, can never have any point of intersection.
Formula Used:
We are going to use the formula of calculating the value of the variable by using Determinant:
Determinant, \[D = {b^2} - 4ac\]
and, \[x = \dfrac{{ - b \pm \sqrt D }}{{2a}}\].
Complete step by step answer:
Say, we have to factorize a quadratic equation \[a{x^2} + bx + c\].
The formula for finding determinant is:
\[D = {b^2} - 4ac\]
Now, we put in the value of the determinant into the formula of finding the value of \[x\],
\[x = \dfrac{{ - b \pm \sqrt D }}{{2a}}\]
Then we just simplify and find the value of the roots.
Note: In the given question, we needed to factorize the given polynomial. It is not true that whenever there is a given problem, there will be a solution. So, first, we need to check if there are any solutions that can be possible. If there is, then only we proceed to calculate the solution. There is no point in calculating the solution when there is not any. For instance, there is no solution to the point of intersection of two parallel lines. Two parallel lines never intersect, hence, can never have any point of intersection.
Recently Updated Pages
In cricket, what is a "pink ball" primarily used for?

In cricket, what is the "new ball" phase?

In cricket, what is a "death over"?

What is the "Powerplay" in T20 cricket?

In cricket, what is a "super over"?

In cricket, what is a "tail-ender"?

Trending doubts
Who was the first woman to receive Bharat Ratna?

Write a letter to the principal requesting him to grant class 10 english CBSE

Why is there a time difference of about 5 hours between class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Discuss the main reasons for poverty in India

