Find the range for \[\sinh x+\cosh x\] .
A. \[\left( 1,\infty \right)\]
B. \[\left( 0,\infty \right)\]
C. \[\left( -\infty ,\infty \right)\]
D. \[\left( -\infty ,0 \right)\]
Answer
645k+ views
Hint: Hyperbolic functions are analogs of the ordinary trigonometric functions defined for the hyperbola rather than on the circle. We know the formulae of \[\sinh x=\dfrac{{{e}^{x}}-{{e}^{-x}}}{2}\] and \[\cosh x=\dfrac{{{e}^{x}}+{{e}^{-x}}}{2}\]. By using these formulas first we have to evaluate the value of \[\sinh x+\cosh x\].
Complete step-by-step answer:
We know hyperbolic functions are analogs of the ordinary trigonometric functions defined for the hyperbola rather than on the circle. The two basic hyperbolic functions are \[\sinh x\] and \[\cosh x\]. And we also know the value of \[\sinh x\] and \[\cosh x\].
According to the formulae
\[\sinh x=\dfrac{{{e}^{x}}-{{e}^{-x}}}{2}\]
Now divide each value with “2” we get,
\[\Rightarrow \left( \dfrac{{{e}^{x}}}{2}-\dfrac{{{e}^{-x}}}{2} \right)\]
And,
\[\cosh x=\dfrac{{{e}^{x}}+{{e}^{-x}}}{2}\]
Now divide each value with “2” we get
\[\Rightarrow \left( \dfrac{{{e}^{x}}}{2}+\dfrac{{{e}^{-x}}}{2} \right)\]
Now we have to calculate the range of \[\sinh x+\cosh x\].
By adding the value of \[\sinh x\] and \[\cosh x\] we have,
\[\begin{align}
& \sinh x+\cosh x \\
& \Rightarrow \left( \dfrac{{{e}^{x}}}{2}-\dfrac{{{e}^{-x}}}{2} \right)+\left( \dfrac{{{e}^{x}}}{2}+\dfrac{{{e}^{-x}}}{2} \right) \\
& \Rightarrow \dfrac{2{{e}^{x}}}{2} \\
& \Rightarrow {{e}^{x}} \\
\end{align}\]
Now we have to evaluate the range of \[{{e}^{x}}\].
The domain is the subset of \[\mathbb{R}\]for which all operations in the function's formula make sense.
Since \[e\] is a positive real constant, it can be raised to any real power, so the domain is not limited. It is \[\mathbb{R}\]. Where \[\mathbb{R}\] is the real number.
Since a positive real constant is raised to a real power, the result is always positive, and is never equal to zero. If the power is to equal zero its base must equal zero, and its exponent must be different from zero it is not possible in that case. So the range is all positive real numbers without zero.
So the range of the function is \[\left( 0,+\infty \right)\](Option B).
Note: Students have to understand the value of function and what is the value of \[\mathbb{R}\]. Students have to remember the hyperbolic functions formulae and they have to know how to draw the \[\sinh x\] and \[\cosh x\] graphs. Understanding of \[e\] and how it works is also very important for solving this problem.
Complete step-by-step answer:
We know hyperbolic functions are analogs of the ordinary trigonometric functions defined for the hyperbola rather than on the circle. The two basic hyperbolic functions are \[\sinh x\] and \[\cosh x\]. And we also know the value of \[\sinh x\] and \[\cosh x\].
According to the formulae
\[\sinh x=\dfrac{{{e}^{x}}-{{e}^{-x}}}{2}\]
Now divide each value with “2” we get,
\[\Rightarrow \left( \dfrac{{{e}^{x}}}{2}-\dfrac{{{e}^{-x}}}{2} \right)\]
And,
\[\cosh x=\dfrac{{{e}^{x}}+{{e}^{-x}}}{2}\]
Now divide each value with “2” we get
\[\Rightarrow \left( \dfrac{{{e}^{x}}}{2}+\dfrac{{{e}^{-x}}}{2} \right)\]
Now we have to calculate the range of \[\sinh x+\cosh x\].
By adding the value of \[\sinh x\] and \[\cosh x\] we have,
\[\begin{align}
& \sinh x+\cosh x \\
& \Rightarrow \left( \dfrac{{{e}^{x}}}{2}-\dfrac{{{e}^{-x}}}{2} \right)+\left( \dfrac{{{e}^{x}}}{2}+\dfrac{{{e}^{-x}}}{2} \right) \\
& \Rightarrow \dfrac{2{{e}^{x}}}{2} \\
& \Rightarrow {{e}^{x}} \\
\end{align}\]
Now we have to evaluate the range of \[{{e}^{x}}\].
The domain is the subset of \[\mathbb{R}\]for which all operations in the function's formula make sense.
Since \[e\] is a positive real constant, it can be raised to any real power, so the domain is not limited. It is \[\mathbb{R}\]. Where \[\mathbb{R}\] is the real number.
Since a positive real constant is raised to a real power, the result is always positive, and is never equal to zero. If the power is to equal zero its base must equal zero, and its exponent must be different from zero it is not possible in that case. So the range is all positive real numbers without zero.
So the range of the function is \[\left( 0,+\infty \right)\](Option B).
Note: Students have to understand the value of function and what is the value of \[\mathbb{R}\]. Students have to remember the hyperbolic functions formulae and they have to know how to draw the \[\sinh x\] and \[\cosh x\] graphs. Understanding of \[e\] and how it works is also very important for solving this problem.
Recently Updated Pages
The given figure shows two endocrine glands marked class 11 biology NEET_UG

Match columnI with columnII and select the correct class 11 biology NEET

Match column I with column II and select the correct class 11 biology NEET_UG

Which floral family has left 9 right + 1 arrangement class 11 biology NEET_UG

Which is not a variety of sheep A Lohi B Beetal C Nellore class 11 biology NEET_UG

Match column I with column II and select the correct class 11 biology NEET_UG

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

