
Find the quadratic equation whose roots are $-5$ and $-2$ .
Answer
588.3k+ views
Hint: First assume a quadratic equation in any form. Apply conditions for sum of roots and product of roots. By this find the values of variables in the quadratic equation. These values can be substituted back into the equation. This equation is the required result.
Complete step-by-step answer:
Given the roots of the quadratic equation are written in the form of $-5$ and $-2$ .
Let the two roots be denoted by variables m, n
Let us assume the first root, $-5$ is denoted by m.
Let us assume the second root, $-2$ is denoted by n.
Let us assume the required quadratic equation as:
$a{{x}^{2}}+bx+c=0$ ……………………………….. (1)
By dividing with ‘a’ on both sides, we get it as:
$\dfrac{a{{x}^{2}}+bx+c}{a}=\dfrac{0}{a}$
By basic knowledge of the fractions, we know the relation:
$\dfrac{A+B+C}{D}=\dfrac{A}{D}+\dfrac{B}{D}+\dfrac{C}{D}$
By using this here, we can write the equation as:
$\dfrac{a{{x}^{2}}}{a}+\dfrac{bx}{a}+\dfrac{c}{a}=\dfrac{0}{a}$
By simplifying the above equation, we can write it as:
$\dfrac{a{{x}^{2}}}{a}+\dfrac{bx}{a}+\dfrac{c}{a}=0$
By cancelling the common terms, we can write it as:
${{x}^{2}}+\dfrac{b}{a}x+\dfrac{c}{a}=\dfrac{0}{a}$ ……………………. (2)
By basic knowledge of equation, we know that for a quadratic equation, we have relations such as:
Sum of roots of equation (1), is equal to $\dfrac{-b}{a}$ .
Product of roots of equation (1), is equal to $\dfrac{c}{a}$ .
Writing the sum of roots statements mathematically, we get it as:
$m+n=\dfrac{-b}{a}$
By substituting m, n we get the above equation in form of:
$-5-2=\dfrac{-b}{a}$
By cancelling the minus sign we can write the equation:
$\dfrac{b}{a}=7$ ……………………….. (3)
Writing product of roots statement mathematically, we get it as:
$m.n=\dfrac{c}{a}$
By substituting the values of m, n, we get it as:
$\left( -5 \right).\left( -2 \right)=\dfrac{c}{a}$
By simplifying equation (4) (3) in equation (2) we get:
${{x}^{2}}+7x+10=0$ is an equation with roots $-5,-2$ .
Note: Be careful while taking the sum of roots formula itself as ‘-‘ sign. If you miss that then you will get $\dfrac{b}{a}$ value as -7. Then the whole equation you present will be wrong. While taking product students confuse and write $-5\times -2$ is $-10$ but it is +10. So, be careful at this step.
Complete step-by-step answer:
Given the roots of the quadratic equation are written in the form of $-5$ and $-2$ .
Let the two roots be denoted by variables m, n
Let us assume the first root, $-5$ is denoted by m.
Let us assume the second root, $-2$ is denoted by n.
Let us assume the required quadratic equation as:
$a{{x}^{2}}+bx+c=0$ ……………………………….. (1)
By dividing with ‘a’ on both sides, we get it as:
$\dfrac{a{{x}^{2}}+bx+c}{a}=\dfrac{0}{a}$
By basic knowledge of the fractions, we know the relation:
$\dfrac{A+B+C}{D}=\dfrac{A}{D}+\dfrac{B}{D}+\dfrac{C}{D}$
By using this here, we can write the equation as:
$\dfrac{a{{x}^{2}}}{a}+\dfrac{bx}{a}+\dfrac{c}{a}=\dfrac{0}{a}$
By simplifying the above equation, we can write it as:
$\dfrac{a{{x}^{2}}}{a}+\dfrac{bx}{a}+\dfrac{c}{a}=0$
By cancelling the common terms, we can write it as:
${{x}^{2}}+\dfrac{b}{a}x+\dfrac{c}{a}=\dfrac{0}{a}$ ……………………. (2)
By basic knowledge of equation, we know that for a quadratic equation, we have relations such as:
Sum of roots of equation (1), is equal to $\dfrac{-b}{a}$ .
Product of roots of equation (1), is equal to $\dfrac{c}{a}$ .
Writing the sum of roots statements mathematically, we get it as:
$m+n=\dfrac{-b}{a}$
By substituting m, n we get the above equation in form of:
$-5-2=\dfrac{-b}{a}$
By cancelling the minus sign we can write the equation:
$\dfrac{b}{a}=7$ ……………………….. (3)
Writing product of roots statement mathematically, we get it as:
$m.n=\dfrac{c}{a}$
By substituting the values of m, n, we get it as:
$\left( -5 \right).\left( -2 \right)=\dfrac{c}{a}$
By simplifying equation (4) (3) in equation (2) we get:
${{x}^{2}}+7x+10=0$ is an equation with roots $-5,-2$ .
Note: Be careful while taking the sum of roots formula itself as ‘-‘ sign. If you miss that then you will get $\dfrac{b}{a}$ value as -7. Then the whole equation you present will be wrong. While taking product students confuse and write $-5\times -2$ is $-10$ but it is +10. So, be careful at this step.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

