Find the product using suitable properties.
$ 7\times \left( 50-2 \right) $
Answer
642.3k+ views
Hint: In order to solve this problem, we need to understand the distributive law of multiplication. The distributive property of multiplication over addition or subtraction can be used when a number is multiplied by a summation or subtraction of numbers. In the case of two brackets of multiplication, we can expand any bracket first. The answer will not change.
Complete step-by-step answer:
To solve this problem, we need to use the distributive property of multiplication
Let’s first understand what distributive law of multiplication means.
The distributive property of multiplication over addition or subtraction can be used when a number is multiplied by a summation or subtraction of numbers.
It is expressed mathematically as follows,
$ a\left( b+c \right)=ab+bc $
Where, a, b, c are just the constants.
In this problem, we can write 7 as 10 – 3.
Therefore, the expression becomes $ \left( 10-3 \right)\left( 50-2 \right) $ .
In this sum, we have two brackets with subtraction.
We need to open any bracket and perform distributive law.
Opening the first bracket we get,
$ \left( 10-3 \right)\left( 50-2 \right)=10\left( 50-2 \right)-3\left( 50-2 \right) $
Now, we can again use the distributive law of multiplication for each of the brackets,
We can simplify by,
$ 10\left( 50-2 \right)-3\left( 50-2 \right)=\left( 10\times 50 \right)+\left( 10\times -2 \right)+\left( -3\times 50 \right)+\left( -3\times -2 \right) $
Simplifying further we get,
$ \left( 10-3 \right)\left( 50-2 \right)=\left( 500 \right)+\left( -20 \right)+\left( -150 \right)+\left( 6 \right) $
Then the product of a negative and a positive number is always a negative number.
Therefore, $ \left( 10\times -2 \right)=-20 $ .
And the product of a negative and a negative number is always a positive number.
Therefore, $ \left( -3\times -2 \right)=+6 $ .
$ \left( 10-3 \right)\left( 50-2 \right)=336 $ .
Therefore, the product using the distributive law of multiplication is 336.
Note: We will get the same answer expanding the second bracket first. We can show that as follows,
\[\begin{align}
& \left( 10-3 \right)\left( 50-2 \right)=50\left( 10-3 \right)-2\left( 10-3 \right) \\
& =\left( 500\times 10 \right)+\left( 50\times -3 \right)+\left( -2\times 10 \right)+\left( -2\times -3 \right) \\
& =500-150-20+6 \\
Complete step-by-step answer:
To solve this problem, we need to use the distributive property of multiplication
Let’s first understand what distributive law of multiplication means.
The distributive property of multiplication over addition or subtraction can be used when a number is multiplied by a summation or subtraction of numbers.
It is expressed mathematically as follows,
$ a\left( b+c \right)=ab+bc $
Where, a, b, c are just the constants.
In this problem, we can write 7 as 10 – 3.
Therefore, the expression becomes $ \left( 10-3 \right)\left( 50-2 \right) $ .
In this sum, we have two brackets with subtraction.
We need to open any bracket and perform distributive law.
Opening the first bracket we get,
$ \left( 10-3 \right)\left( 50-2 \right)=10\left( 50-2 \right)-3\left( 50-2 \right) $
Now, we can again use the distributive law of multiplication for each of the brackets,
We can simplify by,
$ 10\left( 50-2 \right)-3\left( 50-2 \right)=\left( 10\times 50 \right)+\left( 10\times -2 \right)+\left( -3\times 50 \right)+\left( -3\times -2 \right) $
Simplifying further we get,
$ \left( 10-3 \right)\left( 50-2 \right)=\left( 500 \right)+\left( -20 \right)+\left( -150 \right)+\left( 6 \right) $
Then the product of a negative and a positive number is always a negative number.
Therefore, $ \left( 10\times -2 \right)=-20 $ .
And the product of a negative and a negative number is always a positive number.
Therefore, $ \left( -3\times -2 \right)=+6 $ .
$ \left( 10-3 \right)\left( 50-2 \right)=336 $ .
Therefore, the product using the distributive law of multiplication is 336.
Note: We will get the same answer expanding the second bracket first. We can show that as follows,
\[\begin{align}
& \left( 10-3 \right)\left( 50-2 \right)=50\left( 10-3 \right)-2\left( 10-3 \right) \\
& =\left( 500\times 10 \right)+\left( 50\times -3 \right)+\left( -2\times 10 \right)+\left( -2\times -3 \right) \\
& =500-150-20+6 \\
Recently Updated Pages
Match columnI with columnII and choose the correct class 12 biology NEET_UG

Match columnI with columnII and choose the correct class 12 biology NEET_UG

Match columnI with columnII and choose the correct class 12 biology NEET_UG

Which plant will lose its economic value if its fruits class 12 biology NEET_UG

The given figure shows two endocrine glands marked class 11 biology NEET_UG

Human insulin is being commercially produced from a class 12 biology NEET_UG

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

One cusec is equal to how many liters class 8 maths CBSE

Give me the opposite gender of Duck class 8 english CBSE

Full form of STD, ISD and PCO

Answer the following in a phrase or sentence Why did class 8 english CBSE


