How do you find the product of \[(7x + 4)(9x + 8)?\]
Answer
602.7k+ views
Hint: Here, we have to find out the product of two expressions. Now, we will multiply any term by another one, as the associative law of multiplication is an identity property. After doing some simplification we get the required answer.
Complete step-by-step solution:
We have to find the product of \[(7x + 4)\] and \[(9x + 8)\].
So, we can write this in the following way:
\[ \Rightarrow (7x + 4) \times (9x + 8)\]
So, firstly we will multiply the first expression by the first term in the second expression and then we will multiply the first expression by the second term in the second expression.
So, we can rewrite the above expression like following way:
\[ \Rightarrow (7x + 4) \times (9x + 8)\]
\[ \Rightarrow \{ (7x + 4) \times 9x\} + \{ (7x + 4) \times 8\} .\]
Now, we need to multiply the first terms and second terms accordingly:
\[ \Rightarrow (7x + 4) \times (9x + 8)\]
\[ \Rightarrow \{ (7x + 4) \times 9x\} + \{ (7x + 4) \times 8\} .\]
Now, perform the rest of the multiplication, we get:
\[ \Rightarrow \{ (9 \times 7 \times {x^2}) + (4 \times 9x)\} + \{ (7x \times 8) + (4 \times 8)\} .\]
By performing further multiplication and addition, we get:
\[ \Rightarrow (63{x^2} + 36x) + (56x + 32).\]
After re arrangements, we get:
\[ \Rightarrow (63{x^2} + 36x + 56x + 32).\]
Now, we will add the terms that have the variable of the same degree.
So,
\[ \Rightarrow (7x + 4) \times (9x + 8)\]
\[ \Rightarrow (63{x^2} + 92x + 32).\]
\[\therefore \]The answer of the product is \[(63{x^2} + 92x + 32).\]
Note: Points to remember:
We need to add those variable terms that have the same degree.
Also, if constant terms are more than one, we need to add them separately.
Algebraic production of two terms defines by the following rules:
\[(1)\] Multiply only same degree variables.
\[(2)\] Multiplication of ‘\[ + \]’ and ‘\[ - \]’ gives us the ‘\[ - \]’ sign always.
\[(3)\] Always add same degree variables with variables and constant terms with constant terms.
\[(4)\] BODMAS rule is the same as the rest of multiplications.
Complete step-by-step solution:
We have to find the product of \[(7x + 4)\] and \[(9x + 8)\].
So, we can write this in the following way:
\[ \Rightarrow (7x + 4) \times (9x + 8)\]
So, firstly we will multiply the first expression by the first term in the second expression and then we will multiply the first expression by the second term in the second expression.
So, we can rewrite the above expression like following way:
\[ \Rightarrow (7x + 4) \times (9x + 8)\]
\[ \Rightarrow \{ (7x + 4) \times 9x\} + \{ (7x + 4) \times 8\} .\]
Now, we need to multiply the first terms and second terms accordingly:
\[ \Rightarrow (7x + 4) \times (9x + 8)\]
\[ \Rightarrow \{ (7x + 4) \times 9x\} + \{ (7x + 4) \times 8\} .\]
Now, perform the rest of the multiplication, we get:
\[ \Rightarrow \{ (9 \times 7 \times {x^2}) + (4 \times 9x)\} + \{ (7x \times 8) + (4 \times 8)\} .\]
By performing further multiplication and addition, we get:
\[ \Rightarrow (63{x^2} + 36x) + (56x + 32).\]
After re arrangements, we get:
\[ \Rightarrow (63{x^2} + 36x + 56x + 32).\]
Now, we will add the terms that have the variable of the same degree.
So,
\[ \Rightarrow (7x + 4) \times (9x + 8)\]
\[ \Rightarrow (63{x^2} + 92x + 32).\]
\[\therefore \]The answer of the product is \[(63{x^2} + 92x + 32).\]
Note: Points to remember:
We need to add those variable terms that have the same degree.
Also, if constant terms are more than one, we need to add them separately.
Algebraic production of two terms defines by the following rules:
\[(1)\] Multiply only same degree variables.
\[(2)\] Multiplication of ‘\[ + \]’ and ‘\[ - \]’ gives us the ‘\[ - \]’ sign always.
\[(3)\] Always add same degree variables with variables and constant terms with constant terms.
\[(4)\] BODMAS rule is the same as the rest of multiplications.
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