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Find the population of village S if the population of village X below the poverty line in 1997 is $12160$.Proportion of population of sense villages in $1997$ R, S, T, V, X, Y, Z is given in percentage. R$16%$ S$11%$ T $21%$V$10%$ X$16%$ Y$15%$ Z$11%$

Last updated date: 15th Jun 2024
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Hint: In this problem we will suppose that the population is $x$ then calculate the population of each section using the percentage of each section. Using ratio and proportion we will find the exact population of the village.
If suppose section A has y percent then its population $=\dfrac{A}{100}\times Total\text{ }Population$

Given, the population of village X below the poverty line is $12160$. …. (i)
Now, let the population of village X be $x$. ……. (ii)
Then, $38\%$ of $x$$= 12160$ [from eq, (i) & (ii)]
Because, $38\%$ is the population of village X below the poverty line.
$\Rightarrow \,38\% \,of\,x = 12160\,$
$\Rightarrow \,\dfrac{{38}}{{100}} \times \,x = 12160\,$
$\Rightarrow \,38 \times \,x = 12160 \times 100\,$
$\Rightarrow \,\,x = \dfrac{{12160 \times 100}}{{38}}$
$\Rightarrow \,\,x = 320 \times 100$
$\Rightarrow \,\,x = 32000$
Now, if she the total population of village S, then
Given, percentage population of village X$= 16\%$
Percentage population of village S$= 11\%$
Population of village X$= x = 32000$
Population of village S$= s$
By comparing quantities
Ratio of percentage population of both village X and S $=$Ratio of population of village X and S.
$16:11 = 32000:S$
$\Rightarrow \dfrac{{16}}{{11}} = \dfrac{{32000}}{S}$
$\Rightarrow \dfrac{{16 \times S}}{S} = 32000 \times 11$
$\Rightarrow$$S = \dfrac{{32000 \times 11}}{{16}}$
$\Rightarrow$$S = 2000 \times 11$
$\Rightarrow$$S = 22000$

Hence, the population of village S is $22000$.

Note: The above given diagram in the question represents a pie chart. A pie chart is a circular statistical graphic which is divided into many slices to represent the numerical proportions.