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Find the population of village S if the population of village X below the poverty line in 1997 is \[12160\].
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Proportion of population of sense villages in \[1997\] R, S, T, V, X, Y, Z is given in percentage.
T \[21%\]

Last updated date: 15th Jun 2024
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Hint: In this problem we will suppose that the population is $x$ then calculate the population of each section using the percentage of each section. Using ratio and proportion we will find the exact population of the village.
If suppose section A has y percent then its population $=\dfrac{A}{100}\times Total\text{ }Population$

Complete step-by-step answer:
Given, the population of village X below the poverty line is \[12160\]. …. (i)
Now, let the population of village X be \[x\]. ……. (ii)
Then, \[38\% \] of \[x\]\[ = 12160\] [from eq, (i) & (ii)]
Because, \[38\% \] is the population of village X below the poverty line.
\[ \Rightarrow \,38\% \,of\,x = 12160\,\]
\[ \Rightarrow \,\dfrac{{38}}{{100}} \times \,x = 12160\,\]
\[ \Rightarrow \,38 \times \,x = 12160 \times 100\,\]
\[ \Rightarrow \,\,x = \dfrac{{12160 \times 100}}{{38}}\]
\[ \Rightarrow \,\,x = 320 \times 100\]
\[ \Rightarrow \,\,x = 32000\]
Now, if she the total population of village S, then
Given, percentage population of village X\[ = 16\% \]
Percentage population of village S\[ = 11\% \]
Population of village X\[ = x = 32000\]
Population of village S\[ = s\]
By comparing quantities
Ratio of percentage population of both village X and S \[ = \]Ratio of population of village X and S.
\[16:11 = 32000:S\]
\[ \Rightarrow \dfrac{{16}}{{11}} = \dfrac{{32000}}{S}\]
\[ \Rightarrow \dfrac{{16 \times S}}{S} = 32000 \times 11\]
$\Rightarrow$\[S = \dfrac{{32000 \times 11}}{{16}}\]
$\Rightarrow$\[S = 2000 \times 11\]
$\Rightarrow$\[S = 22000\]

Hence, the population of village S is \[22000\].

Note: The above given diagram in the question represents a pie chart. A pie chart is a circular statistical graphic which is divided into many slices to represent the numerical proportions.