
Find the $pH$ of a $0.001M$ $NaOH$ solution will be?
Answer
560.1k+ views
Hint: We can first write the dissociation of sodium hydroxide into its constituent ions. From this, since it is a base, we can get the concentration of the hydroxyl ions. Taking negative logarithms of this will give us the $pOH$ value. As we know, the sum of $pH$ and $pOH$ is $14$. Hence, we can subtract the $pOH$ value from $14$ to get the $pH$ value.
Formulas used: $pOH = - \log [O{H^ - }]$
Where $pOH$ is the concentration of the hydroxyl ions.
$pOH + pH = 14$
Where $pH$ and $pOH$ represents the potential of hydrogen ions and hydroxyl ions respectively.
Complete step by step answer:
Since, the concentration of sodium hydroxide is given, let us see how it dissociates, to find the concentration of hydroxyl ions.
$NaOH \rightleftharpoons N{a^ + } + O{H^ - }$
Since the stoichiometric coefficients (number of moles which react according to the balanced chemical equation) of both $NaOH$ and $O{H^ - }$ are the same, their concentrations will also be the same. Hence:
$[NaOH] = [O{H^ - }] = 0.001M$
As we know, taking the negative logarithm of the concentration of $O{H^ - }$ ion will give us the $pOH$ value of the solution:
$pOH = - \log [O{H^ - }]$
Where $pOH$ is the concentration of the hydroxyl ions
Hence, substituting the concentration value in this equation, we get:
$pOH = - \log (0.001) = - ( - 3)$
$ \Rightarrow pOH = 3$
The sum of values of $pH$ and $pOH$ is $14$. Hence:
$pOH + pH = 14 \Rightarrow pH = 14 - pOH$
Where $pH$ and $pOH$ represents the potential of hydrogen ions and hydroxyl ions respectively.
Substituting the value of $pOH = 3$ in this, we get:
$pH = 14 - 3 = 11$
Hence, the $pH$ of the given solution of sodium hydroxide is $11$
Note: $pH$ of a solution tells us how basic or acidic a particular solution is. A $pH$ of less than seven indicates an acidic solution, while a $pH$ of more than seven indicates a basic solution. Note that the $pH$ of pure water is taken as seven. $pH$ of a solution can be measured using $pH$ papers, which provide a range of colours to compare with or using digital $pH$ meters, which gives a more accurate value.
Formulas used: $pOH = - \log [O{H^ - }]$
Where $pOH$ is the concentration of the hydroxyl ions.
$pOH + pH = 14$
Where $pH$ and $pOH$ represents the potential of hydrogen ions and hydroxyl ions respectively.
Complete step by step answer:
Since, the concentration of sodium hydroxide is given, let us see how it dissociates, to find the concentration of hydroxyl ions.
$NaOH \rightleftharpoons N{a^ + } + O{H^ - }$
Since the stoichiometric coefficients (number of moles which react according to the balanced chemical equation) of both $NaOH$ and $O{H^ - }$ are the same, their concentrations will also be the same. Hence:
$[NaOH] = [O{H^ - }] = 0.001M$
As we know, taking the negative logarithm of the concentration of $O{H^ - }$ ion will give us the $pOH$ value of the solution:
$pOH = - \log [O{H^ - }]$
Where $pOH$ is the concentration of the hydroxyl ions
Hence, substituting the concentration value in this equation, we get:
$pOH = - \log (0.001) = - ( - 3)$
$ \Rightarrow pOH = 3$
The sum of values of $pH$ and $pOH$ is $14$. Hence:
$pOH + pH = 14 \Rightarrow pH = 14 - pOH$
Where $pH$ and $pOH$ represents the potential of hydrogen ions and hydroxyl ions respectively.
Substituting the value of $pOH = 3$ in this, we get:
$pH = 14 - 3 = 11$
Hence, the $pH$ of the given solution of sodium hydroxide is $11$
Note: $pH$ of a solution tells us how basic or acidic a particular solution is. A $pH$ of less than seven indicates an acidic solution, while a $pH$ of more than seven indicates a basic solution. Note that the $pH$ of pure water is taken as seven. $pH$ of a solution can be measured using $pH$ papers, which provide a range of colours to compare with or using digital $pH$ meters, which gives a more accurate value.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

State the laws of reflection of light

Name the metals and nonmetals in the first twenty class 11 chemistry CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

