
Find the perimeter of the adjoined figure, which is semicircle, includes its diameter :
Answer
541.2k+ views
Hint: To find the perimeter of the figure we use the formula of the perimeter of semi-circle which is given as:
Perimeter of the semi-circle is: \[\left( \pi +2 \right)\dfrac{D}{2}\].
where D is the diameter of the figure.
Complete step by step solution:
Let us find the perimeter of the semi-circle and to find the perimeter of the semi-circle we use the formula of the semi-circle as:
Perimeter of the semi-circle is: \[\left( \pi +2 \right)\dfrac{D}{2}\]
According to the question given, the value of the diameter D is given as \[10\text{ }cm\]. Now placing the value of the diameter in the above formula as:
\[\Rightarrow \left( \pi +2 \right)\dfrac{10}{2}\]cm
Removing the bracket and multiplying the values of \[\dfrac{10}{2}\]to both \[\pi ,2\] we get the equation as:
\[\Rightarrow \left( \pi +2 \right)5\] cm
\[\Rightarrow 5\pi +10\] cm
Converting the value of the \[\pi \] into \[3.14\] and placing it in the above equation, we get the value of the perimeter is given as:
\[\Rightarrow 5\times 3.14+10\] cm
\[\Rightarrow 25.71\] cm
Therefore, the value of the perimeter of the semi-circle is given as \[25.71\] cm.
Note: The perimeter of the circle is given as \[\pi D\] and the perimeter of the semi-circle is actually divided into two parts with one part of the semicircle is the diameter line and the second part of the circle is the arc. Hence, the perimeter of the semicircle is equal to the sum of the perimeter of the arc and diameter of the semi-circle. Perimeter of the semi-circle = Perimeter of the arc + Perimeter of the diameter line.
\[\left( \pi +2 \right)r=\pi r+2r\]
Perimeter of the semi-circle is: \[\left( \pi +2 \right)\dfrac{D}{2}\].
where D is the diameter of the figure.
Complete step by step solution:
Let us find the perimeter of the semi-circle and to find the perimeter of the semi-circle we use the formula of the semi-circle as:
Perimeter of the semi-circle is: \[\left( \pi +2 \right)\dfrac{D}{2}\]
According to the question given, the value of the diameter D is given as \[10\text{ }cm\]. Now placing the value of the diameter in the above formula as:
\[\Rightarrow \left( \pi +2 \right)\dfrac{10}{2}\]cm
Removing the bracket and multiplying the values of \[\dfrac{10}{2}\]to both \[\pi ,2\] we get the equation as:
\[\Rightarrow \left( \pi +2 \right)5\] cm
\[\Rightarrow 5\pi +10\] cm
Converting the value of the \[\pi \] into \[3.14\] and placing it in the above equation, we get the value of the perimeter is given as:
\[\Rightarrow 5\times 3.14+10\] cm
\[\Rightarrow 25.71\] cm
Therefore, the value of the perimeter of the semi-circle is given as \[25.71\] cm.
Note: The perimeter of the circle is given as \[\pi D\] and the perimeter of the semi-circle is actually divided into two parts with one part of the semicircle is the diameter line and the second part of the circle is the arc. Hence, the perimeter of the semicircle is equal to the sum of the perimeter of the arc and diameter of the semi-circle. Perimeter of the semi-circle = Perimeter of the arc + Perimeter of the diameter line.
\[\left( \pi +2 \right)r=\pi r+2r\]
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

