
Find the perimeter of the adjoined figure, which is semicircle, includes its diameter :
Answer
542.1k+ views
Hint: To find the perimeter of the figure we use the formula of the perimeter of semi-circle which is given as:
Perimeter of the semi-circle is: \[\left( \pi +2 \right)\dfrac{D}{2}\].
where D is the diameter of the figure.
Complete step by step solution:
Let us find the perimeter of the semi-circle and to find the perimeter of the semi-circle we use the formula of the semi-circle as:
Perimeter of the semi-circle is: \[\left( \pi +2 \right)\dfrac{D}{2}\]
According to the question given, the value of the diameter D is given as \[10\text{ }cm\]. Now placing the value of the diameter in the above formula as:
\[\Rightarrow \left( \pi +2 \right)\dfrac{10}{2}\]cm
Removing the bracket and multiplying the values of \[\dfrac{10}{2}\]to both \[\pi ,2\] we get the equation as:
\[\Rightarrow \left( \pi +2 \right)5\] cm
\[\Rightarrow 5\pi +10\] cm
Converting the value of the \[\pi \] into \[3.14\] and placing it in the above equation, we get the value of the perimeter is given as:
\[\Rightarrow 5\times 3.14+10\] cm
\[\Rightarrow 25.71\] cm
Therefore, the value of the perimeter of the semi-circle is given as \[25.71\] cm.
Note: The perimeter of the circle is given as \[\pi D\] and the perimeter of the semi-circle is actually divided into two parts with one part of the semicircle is the diameter line and the second part of the circle is the arc. Hence, the perimeter of the semicircle is equal to the sum of the perimeter of the arc and diameter of the semi-circle. Perimeter of the semi-circle = Perimeter of the arc + Perimeter of the diameter line.
\[\left( \pi +2 \right)r=\pi r+2r\]
Perimeter of the semi-circle is: \[\left( \pi +2 \right)\dfrac{D}{2}\].
where D is the diameter of the figure.
Complete step by step solution:
Let us find the perimeter of the semi-circle and to find the perimeter of the semi-circle we use the formula of the semi-circle as:
Perimeter of the semi-circle is: \[\left( \pi +2 \right)\dfrac{D}{2}\]
According to the question given, the value of the diameter D is given as \[10\text{ }cm\]. Now placing the value of the diameter in the above formula as:
\[\Rightarrow \left( \pi +2 \right)\dfrac{10}{2}\]cm
Removing the bracket and multiplying the values of \[\dfrac{10}{2}\]to both \[\pi ,2\] we get the equation as:
\[\Rightarrow \left( \pi +2 \right)5\] cm
\[\Rightarrow 5\pi +10\] cm
Converting the value of the \[\pi \] into \[3.14\] and placing it in the above equation, we get the value of the perimeter is given as:
\[\Rightarrow 5\times 3.14+10\] cm
\[\Rightarrow 25.71\] cm
Therefore, the value of the perimeter of the semi-circle is given as \[25.71\] cm.
Note: The perimeter of the circle is given as \[\pi D\] and the perimeter of the semi-circle is actually divided into two parts with one part of the semicircle is the diameter line and the second part of the circle is the arc. Hence, the perimeter of the semicircle is equal to the sum of the perimeter of the arc and diameter of the semi-circle. Perimeter of the semi-circle = Perimeter of the arc + Perimeter of the diameter line.
\[\left( \pi +2 \right)r=\pi r+2r\]
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

