Question

Find the perimeter of a square.

\[\begin{align}
  & (A)13.2in \\
 & (B)23.2in \\
 & (C)33.2in \\
 & (D)43.2in \\
\end{align}\]

Answer 1

Hint: We know that the sum of all the sides of a polygon is said to be the perimeter of a polygon. We know that a square is a quadrilateral. If the side of a square is equal to a, then the perimeter is equal to 4a. From the question, we have to find the side of the square. Now assume this side of the square as a. Now we have to find the value of 4a. This will give the value of the perimeter of the square.

Complete step-by-step solution -
Before solving the question, we should know that the sum of all the sides of a polygon is said to be the perimeter of a polygon.
We know that a quadrilateral is said to be a square if all the adjacent sides of the quadrilateral are equal. Let us assume the side of a square is a, then the side of the square is equal to 4a.

Then the perimeter of a square ABCD = AB + BC + CD + DA.
We know that all the sides of a square are equal.
So, AB = BC = CD = DA = a.
So, the perimeter of square \[=a+a+a+a=4a\]
So, it is clear that if the side of a square is equal to then the perimeter of the square is equal to 4a.
In the question a square is given as shown below:

From the diagram, it is clear that the side of a square is equal to 5.8 in.
We know that if the side of a square is equal to a then the perimeter of the square is equal to 4a. As the side of the square is equal to 5.8 in, then the perimeter of the square is equal to 4(5.8) in.
So, the perimeter of the square is equal to 23.2 in.
Hence, option (B) is correct.

Note: We know that all the sides of the square are equal. In the same way, all the sides of rhombus are equal. If the side of a rhombus is equal to a, then the perimeter of rhombus is equal to 4a. We know that if opposite sides are equal, then the quadrilateral is said to be parallelogram. If the sides of the parallelogram are l and b, then the perimeter of the rectangle is equal to \[2(l+b)\]. In the same way, in the rectangle opposite sides are equal. If the sides of the rectangle are l and b, then the perimeter of the rectangle is equal to \[2(l+b)\].