
Find the number of permutations of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together.
A) \[{}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\]
B) \[{}^{n - 3}{C_{r - 3}}\left( {r - 3} \right)!3!\]
C) \[{}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!\]
D) None of these
Answer
546.9k+ views
Hint:
Here we will first find the possible number of arrangements when the three things come together. Then we will find the number of ways in which all the three objects can be arranged. We will then find the number of ways in which all the \[\left( {r - 3 + 1} \right)\] objects can be arranged. Then we will combine all the ways to find the required number of permutations.
Complete Step by Step Solution:
It is given that 3 particular things must occur together which means the total number of objects that become \[n - 3\] taken things becomes \[r - 3\].
So the number of arrangement when the three things come together is \[ = {}^{n - 3}{C_{r - 3}}\]
Now we will find the number of ways in which all the three objects can be arranged. Therefore, we get
Arrangement of 3 particular things which must occur together is \[ = 3!\]
Now we will find the number of ways in which all the \[\left( {r - 3 + 1} \right)\] objects can be arranged. Therefore, we get
Number of arrangements of the \[\left( {r - 3 + 1} \right)\] objects is \[ = \left( {r - 3 + 1} \right)! = \left( {r - 2} \right)!\]
Now we will write the permutation of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together, we get
Total possible arrangements is \[ = {}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\]
Hence the number of permutations of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together is \[{}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\].
Therefore, option A is the correct option.
Note:
Here we have to note that we need to apply the formula of permutation not the combination for the arrangement of the letters. As a permutation is defined as the different ways in which a collection of items can be arranged. For example: The different ways in which the numbers 1, 2 and 3 can be grouped together, taken all at a time, are\[123,{\rm{ }}132,{\rm{ }}213{\rm{ }}231,{\rm{ }}312,{\rm{ }}321\].
Combinations may be defined as the various ways in which objects from a set may be selected. For example: The different selections possible from the numbers 1, 2, 3 taking 2 at a time, are \[{\rm{12, 23 and 31}}\]
Here we will first find the possible number of arrangements when the three things come together. Then we will find the number of ways in which all the three objects can be arranged. We will then find the number of ways in which all the \[\left( {r - 3 + 1} \right)\] objects can be arranged. Then we will combine all the ways to find the required number of permutations.
Complete Step by Step Solution:
It is given that 3 particular things must occur together which means the total number of objects that become \[n - 3\] taken things becomes \[r - 3\].
So the number of arrangement when the three things come together is \[ = {}^{n - 3}{C_{r - 3}}\]
Now we will find the number of ways in which all the three objects can be arranged. Therefore, we get
Arrangement of 3 particular things which must occur together is \[ = 3!\]
Now we will find the number of ways in which all the \[\left( {r - 3 + 1} \right)\] objects can be arranged. Therefore, we get
Number of arrangements of the \[\left( {r - 3 + 1} \right)\] objects is \[ = \left( {r - 3 + 1} \right)! = \left( {r - 2} \right)!\]
Now we will write the permutation of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together, we get
Total possible arrangements is \[ = {}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\]
Hence the number of permutations of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together is \[{}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\].
Therefore, option A is the correct option.
Note:
Here we have to note that we need to apply the formula of permutation not the combination for the arrangement of the letters. As a permutation is defined as the different ways in which a collection of items can be arranged. For example: The different ways in which the numbers 1, 2 and 3 can be grouped together, taken all at a time, are\[123,{\rm{ }}132,{\rm{ }}213{\rm{ }}231,{\rm{ }}312,{\rm{ }}321\].
Combinations may be defined as the various ways in which objects from a set may be selected. For example: The different selections possible from the numbers 1, 2, 3 taking 2 at a time, are \[{\rm{12, 23 and 31}}\]
Recently Updated Pages
Why is there a time difference of about 5 hours between class 10 social science CBSE

In cricket, what is a "pink ball" primarily used for?

In cricket, what is the "new ball" phase?

In cricket, what is a "death over"?

What is the "Powerplay" in T20 cricket?

In cricket, what is a "super over"?

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

