
Find the number of permutations of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together.
A) \[{}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\]
B) \[{}^{n - 3}{C_{r - 3}}\left( {r - 3} \right)!3!\]
C) \[{}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!\]
D) None of these
Answer
563.1k+ views
Hint:
Here we will first find the possible number of arrangements when the three things come together. Then we will find the number of ways in which all the three objects can be arranged. We will then find the number of ways in which all the \[\left( {r - 3 + 1} \right)\] objects can be arranged. Then we will combine all the ways to find the required number of permutations.
Complete Step by Step Solution:
It is given that 3 particular things must occur together which means the total number of objects that become \[n - 3\] taken things becomes \[r - 3\].
So the number of arrangement when the three things come together is \[ = {}^{n - 3}{C_{r - 3}}\]
Now we will find the number of ways in which all the three objects can be arranged. Therefore, we get
Arrangement of 3 particular things which must occur together is \[ = 3!\]
Now we will find the number of ways in which all the \[\left( {r - 3 + 1} \right)\] objects can be arranged. Therefore, we get
Number of arrangements of the \[\left( {r - 3 + 1} \right)\] objects is \[ = \left( {r - 3 + 1} \right)! = \left( {r - 2} \right)!\]
Now we will write the permutation of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together, we get
Total possible arrangements is \[ = {}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\]
Hence the number of permutations of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together is \[{}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\].
Therefore, option A is the correct option.
Note:
Here we have to note that we need to apply the formula of permutation not the combination for the arrangement of the letters. As a permutation is defined as the different ways in which a collection of items can be arranged. For example: The different ways in which the numbers 1, 2 and 3 can be grouped together, taken all at a time, are\[123,{\rm{ }}132,{\rm{ }}213{\rm{ }}231,{\rm{ }}312,{\rm{ }}321\].
Combinations may be defined as the various ways in which objects from a set may be selected. For example: The different selections possible from the numbers 1, 2, 3 taking 2 at a time, are \[{\rm{12, 23 and 31}}\]
Here we will first find the possible number of arrangements when the three things come together. Then we will find the number of ways in which all the three objects can be arranged. We will then find the number of ways in which all the \[\left( {r - 3 + 1} \right)\] objects can be arranged. Then we will combine all the ways to find the required number of permutations.
Complete Step by Step Solution:
It is given that 3 particular things must occur together which means the total number of objects that become \[n - 3\] taken things becomes \[r - 3\].
So the number of arrangement when the three things come together is \[ = {}^{n - 3}{C_{r - 3}}\]
Now we will find the number of ways in which all the three objects can be arranged. Therefore, we get
Arrangement of 3 particular things which must occur together is \[ = 3!\]
Now we will find the number of ways in which all the \[\left( {r - 3 + 1} \right)\] objects can be arranged. Therefore, we get
Number of arrangements of the \[\left( {r - 3 + 1} \right)\] objects is \[ = \left( {r - 3 + 1} \right)! = \left( {r - 2} \right)!\]
Now we will write the permutation of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together, we get
Total possible arrangements is \[ = {}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\]
Hence the number of permutations of \[n\] distinct things taken \[r\] together, in which 3 particular things must occur together is \[{}^{n - 3}{C_{r - 3}}\left( {r - 2} \right)!3!\].
Therefore, option A is the correct option.
Note:
Here we have to note that we need to apply the formula of permutation not the combination for the arrangement of the letters. As a permutation is defined as the different ways in which a collection of items can be arranged. For example: The different ways in which the numbers 1, 2 and 3 can be grouped together, taken all at a time, are\[123,{\rm{ }}132,{\rm{ }}213{\rm{ }}231,{\rm{ }}312,{\rm{ }}321\].
Combinations may be defined as the various ways in which objects from a set may be selected. For example: The different selections possible from the numbers 1, 2, 3 taking 2 at a time, are \[{\rm{12, 23 and 31}}\]
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

