Question

Find the number of H atoms in $9.033 \times {10^{23}}$ molecules of water.

Answer 1

Hint: The atom is the simplest unit in the matter which combines to form the chemical element. A single water molecule is composed of two hydrogen atoms and one oxygen atom which are oppositely charged and thus attract each other with large force of attraction.

Complete step by step answer:
Given,
The molecule of water is $9.033 \times {10^{23}}$.
The chemical formula of water is ${H_2}O$, where two hydrogen atoms are present and one oxygen atom is present. The two hydrogen atoms are linked with the oxygen atom. The water molecule contains positive charge hydrogen ion and negative charge hydroxide ion. Due to the opposite charged ion, the charges tend to attract each other and keep the water molecule intact and together. The water is neutral in nature so the pH of water is 7.
1 molecule of water ${H_2}O$ contains 2 hydrogen atoms.
It is represented as shown below.
1 molecule of ${H_2}O$ = 2 hydrogen atom
So, $9.033 \times {10^{23}}$ molecules of water contains $2 \times 9.033 \times {10^{23}}$number of atoms.
It is represented as shown below.
$ \Rightarrow (9.033 \times {10^{23}}) \times 2$
$ \Rightarrow 18.066 \times {10^{23}}$
Therefore, the number of H atoms in $9.033 \times {10^{23}}$ molecules of water is $18.066 \times {10^{23}}$.

Additional information: The value $6.022 \times {10^{23}}$ is the Avagadro’s number which represents the particles in moles. The Avagadro’s number is the experimentally determined number. The particles can be electrons, atoms, ions or molecules.

Note:
Don’t get confused by the terms like moles and molecules. Both are different. 1 mole of any chemical compound is equal to the $6.022 \times {10^{23}}$ number of molecules. The atoms combine to form molecule or chemical compounds.