Question

Find the number of atoms in \[48\,g\] of ozone at NTP.

Answer 1

Hint:Here we are going to find the number of atoms for a given quantity of ozone at NTP. Ozone is having a molecular formula of \[{O_3}\]. And NTP stands for Normal Temperature and pressure which means that the conditions are the same as room conditions.

Complete step by step answer:
Let’s start with discussing the NTP for better understanding of the question. NTP stands for normal temperature and pressure, it is a term which is used to define air at \[{25^o}C\] and \[1\] atm pressure. We can see the difference of this term with respect to STP, that is, standard temperature and pressure which stands for \[{0^o}C\] temperature and \[1\] bar pressure.
In the question we are given \[48\,g\] of Ozone, Ozone is having the molecular formula of \[{O_3}\].
The molecular weight of ozone is \[48\,g\]. Hence the moles of ozone given to us can be calculated using
${\text{Moles}} = \dfrac{{{\text{Given Mass}}}}{{{\text{Molecular Mass}}}} = \dfrac{{48}}{{48}} = 1$ Mole of Ozone.
According to Avagadro’s number \[1\] mole of a molecule contains \[6.022 \times {10^{23}}\] molecules.
Hence, \[1\] mole contains \[6.022 \times {10^{23}}\] molecules.
Similarly each molecule of ozone contain \[3\] oxygen atoms, hence
The number of oxygen atoms in \[48\,g\] of ozone,
\[ \Rightarrow 3{\text{ }}X{\text{ }}6.022{\text{ }}X{\text{ }}{10^{23}}\] atoms of oxygen
\[ \Rightarrow 1.81{\text{ }}X{\text{ }}{10^{24}}\] atoms of oxygen.
Hence,
$\therefore $ The answer to this question is \[1.81 \times {10^{24}}\] atoms.


Note:
In many of the questions instead of grams the volume of gas is given along with the volume of the gas. In this usually STP conditions are provided which are \[{0^o}C\] temperature and \[1\] bar pressure. At this condition it is to be noted that the volume of one mole of gas is \[22.4{\text{ L}}\] and using this you can get your answer.