Find the molecular mass (in kilogram) of an ammonia molecule $ N{H_3} $ .
Answer
574.8k+ views
Hint: The importance of the molecular mass is defined by the number of molecules which present in the given moles of the compound. The molecular mass can be calculated using the atomic mass of each of the molecules and the number of molecules involved.
Complete step by step answer
The molecular mass of any specific molecule can be defined according to the different atoms which are involved in the formation of the given molecule. For the formation of $ N{H_3} $ requires one atom of $ N $ and three atoms of $ H $ . Therefore, the atomic mass for each of the elements can be calculated. At first, the atomic mass for $ N $ is $ 14g/mol $ and there is only one $ N $ which is why from there the mass for $ N $ is $ 14g/mol $ . The atomic mass for $ H $ is $ 1g/mol $ and there are three hydrogen atoms involved which form the atomic mass of all $ H $ is $ 3g/mol $ .
Therefore, the molecular mass of the $ N{H_3} $ molecule is formed with the mass of all the atoms involved in the formation of the given molecule. Hence the two atomic masses calculated for $ N $ residue and that of the $ H $ residue will be:
$ N{H_3} = (3 + 14) = 17g/mol $
The number of molecules which are present in one mole of $ N{H_3} $ is $ 6.022 \times {10^{23}} $ . For one molecule of ammonia, the mass would be = $ \dfrac{{17}}{{6.022 \times {{10}^{23}}}}g $ .
Therefore, for each of the molecules the mass will be $ 2.823 \times {10^{ - 23}}g $ or $ 2.823 \times {10^{ - 26}}kg $ .
The calculation of the molecular mass in kilograms is calculated using the factor of $ 1000 $ from the previous mass and the $ N{H_3} $ molecule has the mass $ 2.823 \times {10^{ - 26}}kg $ .
Note
The $ N{H_3} $ molecular mass is at first calculated for one mole and from there the calculation for a single molecule can be done. The kilograms of each of the molecules need to be calculated changing the units for the measurement. But at first, for a specific mole, the number of molecules need to be calculated.
Complete step by step answer
The molecular mass of any specific molecule can be defined according to the different atoms which are involved in the formation of the given molecule. For the formation of $ N{H_3} $ requires one atom of $ N $ and three atoms of $ H $ . Therefore, the atomic mass for each of the elements can be calculated. At first, the atomic mass for $ N $ is $ 14g/mol $ and there is only one $ N $ which is why from there the mass for $ N $ is $ 14g/mol $ . The atomic mass for $ H $ is $ 1g/mol $ and there are three hydrogen atoms involved which form the atomic mass of all $ H $ is $ 3g/mol $ .
Therefore, the molecular mass of the $ N{H_3} $ molecule is formed with the mass of all the atoms involved in the formation of the given molecule. Hence the two atomic masses calculated for $ N $ residue and that of the $ H $ residue will be:
$ N{H_3} = (3 + 14) = 17g/mol $
The number of molecules which are present in one mole of $ N{H_3} $ is $ 6.022 \times {10^{23}} $ . For one molecule of ammonia, the mass would be = $ \dfrac{{17}}{{6.022 \times {{10}^{23}}}}g $ .
Therefore, for each of the molecules the mass will be $ 2.823 \times {10^{ - 23}}g $ or $ 2.823 \times {10^{ - 26}}kg $ .
The calculation of the molecular mass in kilograms is calculated using the factor of $ 1000 $ from the previous mass and the $ N{H_3} $ molecule has the mass $ 2.823 \times {10^{ - 26}}kg $ .
Note
The $ N{H_3} $ molecular mass is at first calculated for one mole and from there the calculation for a single molecule can be done. The kilograms of each of the molecules need to be calculated changing the units for the measurement. But at first, for a specific mole, the number of molecules need to be calculated.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

