Question

Find the mean of the first six multiples of \[3\].

Answer 1

Hint: To solve this question first we have to write \[6\] multiples of the table of \[3\]. Then we have to find the average of all the numbers which have been written. Average is the ratio of the sum of all the numbers to the total number of numbers. Average is also known by the name called mean.

Complete answer: Given,
First sir multiples of \[3\].
To find,
The mean of first sir multiples of \[3\].
So to solve this question first we write First sir multiples of \[3\].
First sir multiples of \[3\] are.
\[3,6,9,12,15,18\]
Now we have to take the average of all these numbers.
Average of all the numbers is the ratio of sum of all the numbers to the total number of numbers.
\[{\text{average of all the numbers = }}\dfrac{{{\text{sum of all the terms}}}}{{total\,number\,of\,terms}}{\text{ }}\]
Sum of all the terms are
\[3 + 6 + 9 + 12 + 15 + 18 = 63\]
Sum of all the terms are \[ = 63\]
And the total number of terms are \[ = 6\]
On putting both these values in the formula of average
\[{\text{average of all the numbers = }}\dfrac{{{\text{sum of all the terms}}}}{{total\,number\,of\,terms}}{\text{ }}\]
On putting the values
\[{\text{average of all the numbers = }}\dfrac{{{\text{63}}}}{6}{\text{ }}\]
On further calculating we got the average
\[{\text{average of all the numbers = }}10.5{\text{ }}\]
Final answer:
The mean (average) of the first six multiples of \[3\].
\[ \Rightarrow {\text{average of all the numbers = }}10.5{\text{ }}\].

Note:
To solve this type of question you must have better knowledge of mean (average). You may commit a mistake in finding the six multiples of \[3\]. After you find all the multiples of \[3\] you have to add all of them divided by the total number of terms in order to find the value of the average of that number. Take a look at the calculation part to get a write the answer.