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Find the mean of the first 10 natural numbers.

Answer
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Hint – In order to solve this problem we need to know that the natural numbers are those which start from 1 and the mean of n numbers is the sum of n numbers divided by n. doing this will solve your problem.

Complete step-by-step answer:

Firstly, a natural number is an integer greater than 0. Natural numbers begin at 1 and increment to infinity: 1, 2, 3, 4, 5, etc.

Therefore, the first ten natural numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.

And the mean of three numbers a, b, c is $\dfrac{{{\text{a + b + c}}}}{{\text{3}}}$.

Then the mean of 10 numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 is:-
$ \Rightarrow \dfrac{{1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10}}{{10}}$

Adding and dividing we get the value of the above term as,
$ \Rightarrow \dfrac{{1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10}}{{10}} = \dfrac{{55}}{{10}} = 5.5$

Hence, the mean of the first 10 natural numbers is 5.5.

Note – In this problem you need to know that the mean of the three numbers a, b, c is $\dfrac{{{\text{a + b + c}}}}{{\text{3}}}$ and the integers greater than zero are natural numbers. Knowing methods to find the mean of number of elements and knowing about natural numbers you will get the right answer.