Find the least number which must be added to each of the following number so as to get a perfect square.$525$
Answer
618.3k+ views
Hint: We will solve the $525$ by square root method. We will solve $525$ by two methods, in the first method, we will take smaller numbers. In the second method, we will take a bigger number to get the perfect square.
Complete step by step solution:
The given number is $525$
Now, we will solve the $525$ to the square root method
Remainder$ = 41,$since remainder is not $0$, so $252$ is not a perfect square. So we will add $4$ in the value $252$ to get a perfect square.
The perfect square number is $ = 525 + 4$
$ = 529$
Now, we will verify the value $529$
Here, remainder is$0$,
So,$529$is a perfect square of $23$.
Additional Information: Properties of square root:
(i) Two square roots can be multiplied$\sqrt 2 $, when multiplied by $\sqrt 3 $, gives $\sqrt 6 $ as a result.
(ii) Two same square roots are multiplied to give anon-square root number. When $\sqrt 3 $ is multiplied by $\sqrt 3 $ we get $3$ as a result.
(iii) If a number ends with an odd number of zeroes, then it cannot have a square root. A square root is only possible for even numbers of zeroes.
Note: In this case, $42 \times 2 = 84$ and $43 \times 3 = 169$. So we choose $3$ as a new digit to be put in divisor and in the quotient. Therefore the remainder here is $0$.
Complete step by step solution:
The given number is $525$
Now, we will solve the $525$ to the square root method
| 2 | $22$ |
| $525$$ - 4$ | |
| $4\underline 2 $ | $125$$ - 84$ |
| $41$ | |
| 2 | $23$ |
| $525$ $ - 4$ | |
| $4\underline 3 $ | $125$$ - 129$ |
| $ - 4$ |
Remainder$ = 41,$since remainder is not $0$, so $252$ is not a perfect square. So we will add $4$ in the value $252$ to get a perfect square.
The perfect square number is $ = 525 + 4$
$ = 529$
Now, we will verify the value $529$
| 2 | $23$ |
| $529$ $ - 4$ | |
| $4\underline 3 $ | $129$$ - 129$ |
| $0$ |
Here, remainder is$0$,
So,$529$is a perfect square of $23$.
Additional Information: Properties of square root:
(i) Two square roots can be multiplied$\sqrt 2 $, when multiplied by $\sqrt 3 $, gives $\sqrt 6 $ as a result.
(ii) Two same square roots are multiplied to give anon-square root number. When $\sqrt 3 $ is multiplied by $\sqrt 3 $ we get $3$ as a result.
(iii) If a number ends with an odd number of zeroes, then it cannot have a square root. A square root is only possible for even numbers of zeroes.
Note: In this case, $42 \times 2 = 84$ and $43 \times 3 = 169$. So we choose $3$ as a new digit to be put in divisor and in the quotient. Therefore the remainder here is $0$.
Recently Updated Pages
Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

Make a sketch of the human nerve cell What function class 10 biology CBSE

Define Potential, Developed, Stock and Reserved resources

