Answer
Verified
380.5k+ views
Hint: In order to compute the LCM and HCF of the given pairs of numbers we study the definitions of the respective terms to find the answer. LCM stands for least common multiple which is a multiple of all the given numbers but the least number of all such multiples. HCF stands for highest common factor which is a common factor for all the given numbers but the highest one in the lot.
Complete step-by-step answer:
(i). Factors of 12 = 1 × 2 × 2 × 3
Factors of 15 = 1 × 3 × 5
Factors of 21 = 1 × 3 × 7
HCF (12, 15, 21) = 3
LCM (12, 15, 21) = 2 × 2 × 3 × 5 × 7 = 420
(ii). Factors of 17 = 1 × 17
Factors of 23 = 1 × 23
Factors of 29 = 1 × 29
HCF (17, 23, 29) = 1
LCM (17, 23, 29) = 1 × 17 × 23 × 29 = 11339
(iii). Factors of 8 = 1 × 2 × 2 × 2
Factors of 9 = 1 × 3 × 3
Factors of 25 = 1 × 5 × 5
HCF (8, 9, 25) = 1
LCM (8, 9, 25) = 2 × 2 × 2 × 3 × 3 × 5 × 5 = 1800
(iv). Factors of 72 = 1 × 2 × 2 × 2 × 3 × 3
Factors of 108 = 1 × 2 × 2 × 3 × 3 × 3
HCF (72, 108) = 2 x 2 x 3 x 3 = 36
LCM (72, 108) = 2 × 2 × 2 × 3 × 3 × 3 = 216
(v). Factors of 306 = 1 × 2 × 3 × 3 × 17
Factors of 657 = 3 × 3 × 73
HCF (306, 657) = 3 x 3 = 9
LCM (306, 657) = 2 × 3 × 3 × 17 × 73 = 22338
Note: In order to solve this type of question the key is to know the concept of prime factorization method. Prime factorization method is nothing but the division of a number into its multiples of prime factors. This helps us look at all the prime numbers that are multiplied to obtain the given number and the numbers of times each prime number is multiplied. Once we express the given number in the form of its prime factors we just look at it and write the LCM and HCF according to their definitions.
Complete step-by-step answer:
(i). Factors of 12 = 1 × 2 × 2 × 3
Factors of 15 = 1 × 3 × 5
Factors of 21 = 1 × 3 × 7
HCF (12, 15, 21) = 3
LCM (12, 15, 21) = 2 × 2 × 3 × 5 × 7 = 420
(ii). Factors of 17 = 1 × 17
Factors of 23 = 1 × 23
Factors of 29 = 1 × 29
HCF (17, 23, 29) = 1
LCM (17, 23, 29) = 1 × 17 × 23 × 29 = 11339
(iii). Factors of 8 = 1 × 2 × 2 × 2
Factors of 9 = 1 × 3 × 3
Factors of 25 = 1 × 5 × 5
HCF (8, 9, 25) = 1
LCM (8, 9, 25) = 2 × 2 × 2 × 3 × 3 × 5 × 5 = 1800
(iv). Factors of 72 = 1 × 2 × 2 × 2 × 3 × 3
Factors of 108 = 1 × 2 × 2 × 3 × 3 × 3
HCF (72, 108) = 2 x 2 x 3 x 3 = 36
LCM (72, 108) = 2 × 2 × 2 × 3 × 3 × 3 = 216
(v). Factors of 306 = 1 × 2 × 3 × 3 × 17
Factors of 657 = 3 × 3 × 73
HCF (306, 657) = 3 x 3 = 9
LCM (306, 657) = 2 × 3 × 3 × 17 × 73 = 22338
Note: In order to solve this type of question the key is to know the concept of prime factorization method. Prime factorization method is nothing but the division of a number into its multiples of prime factors. This helps us look at all the prime numbers that are multiplied to obtain the given number and the numbers of times each prime number is multiplied. Once we express the given number in the form of its prime factors we just look at it and write the LCM and HCF according to their definitions.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
At which age domestication of animals started A Neolithic class 11 social science CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
One cusec is equal to how many liters class 8 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Change the following sentences into negative and interrogative class 10 english CBSE