
How do you find the inverse of $f\left( x \right)=3x-5$ and is it a function?
Answer
564k+ views
Hint: To find the inverse of the given function $f\left( x \right)=3x-5$, first of all, we will assume $f\left( x \right)$ as y and write y in place of $f\left( x \right)$ in the above function. Then, we are going to arrange this equation in such a way so that we get x in terms of y. After that, we have to check whether the inverse of the function that we have calculated is a function or not by checking the condition that only one value is possible corresponding to each x value.
Complete step-by-step answer:
The function given above which we have to find the inverse of is:
$f\left( x \right)=3x-5$
Now, we are going to write y in place of $f\left( x \right)$ in the above equation and we get,
$\Rightarrow y=3x-5$
The function in x written on the R.H.S of the above equation is calculated by writing x in terms of y. For that, we are adding 5 on both the sides of the above equation we get,
$\Rightarrow y+5=3x-5+5$
As you can see that 5 written on the R.H.S of the above equation will be cancelled out and we are left with:
$\Rightarrow y+5=3x$
Now, dividing 3 on both the sides of the above equation we get,
$\Rightarrow \dfrac{y+5}{3}=x$
Now, writing x in place of y and ${{f}^{-1}}\left( x \right)$ in place of x in the above equation we get,
${{f}^{-1}}\left( x \right)=\dfrac{x+5}{3}$
Hence, we have found the inverse of the above function as:
${{f}^{-1}}\left( x \right)=\dfrac{x+5}{3}$
Now, to check whether this inverse is a function or not by taking ${{f}^{-1}}\left( x \right)$ as y in the above equation and then plot the following on the graph we get,
$y=\dfrac{x+5}{3}$
In the above graph, you can see that only one y value is possible corresponding to an x value.
So, this means that the inverse which we have calculated above is a function.
Note: The possible mistake that could be possible in the above problem is that calculation mistake when we are converting x in terms of y so be aware while converting x in terms of y.
In the above solution, we have learnt two concepts. First is, to find the inverse of any function and second is, to check whether an expression is a function or not.
Complete step-by-step answer:
The function given above which we have to find the inverse of is:
$f\left( x \right)=3x-5$
Now, we are going to write y in place of $f\left( x \right)$ in the above equation and we get,
$\Rightarrow y=3x-5$
The function in x written on the R.H.S of the above equation is calculated by writing x in terms of y. For that, we are adding 5 on both the sides of the above equation we get,
$\Rightarrow y+5=3x-5+5$
As you can see that 5 written on the R.H.S of the above equation will be cancelled out and we are left with:
$\Rightarrow y+5=3x$
Now, dividing 3 on both the sides of the above equation we get,
$\Rightarrow \dfrac{y+5}{3}=x$
Now, writing x in place of y and ${{f}^{-1}}\left( x \right)$ in place of x in the above equation we get,
${{f}^{-1}}\left( x \right)=\dfrac{x+5}{3}$
Hence, we have found the inverse of the above function as:
${{f}^{-1}}\left( x \right)=\dfrac{x+5}{3}$
Now, to check whether this inverse is a function or not by taking ${{f}^{-1}}\left( x \right)$ as y in the above equation and then plot the following on the graph we get,
$y=\dfrac{x+5}{3}$
In the above graph, you can see that only one y value is possible corresponding to an x value.
So, this means that the inverse which we have calculated above is a function.
Note: The possible mistake that could be possible in the above problem is that calculation mistake when we are converting x in terms of y so be aware while converting x in terms of y.
In the above solution, we have learnt two concepts. First is, to find the inverse of any function and second is, to check whether an expression is a function or not.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

Chemical formula of Bleaching powder is A Ca2OCl2 B class 11 chemistry CBSE

Name the part of the brain responsible for the precision class 11 biology CBSE

The growth of tendril in pea plants is due to AEffect class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

