
How do you find the integral of $\dfrac{1}{{{{(\cos x)}^2}}}$?
Answer
557.1k+ views
Hint:
As we know about the integral, it is used for finding the areas, volumes and for central points etc. We use it for finding the integration of a particular given identity. It is denoted by the $\int {} $ sign; it is done with respect to a variable which can be $x,y,z$ etc.
Complete step by step solution:
Given that –
According to question integrate ${(\dfrac{1}{{\cos x}})^2}$
Let – $I = {(\dfrac{1}{{\cos x}})^2}$
Now we can write it as ${(\dfrac{1}{{\cos x}})^2} = \dfrac{1}{{{{\cos }^2}x}}$ because both are same in the trigonometry identity
We know that the three basic identity of trigonometry are First is ${\sin ^2}x + {\cos ^2}x = 1$ and second is ${\tan ^2}x + 1 = {\sec ^2}x$ and the third identity is the ${\cot ^2}x + 1 = \cos e{c^2}x$.
We have to know the conversion formula in the trigonometry which are very useful so now we will see them $\dfrac{1}{{\sin x}} = \cos ecx$ and $\dfrac{1}{{\cos x}} = secx$ and $\dfrac{1}{{\tan x}} = \cot x$ now we will use our second formula which is $\dfrac{1}{{\cos x}} = secx$
Now we will integrate the $I$ with respect to $x$
$ = \int I $
$ = \int {\dfrac{1}{{{{\cos }^2}x}}dx} $
Now we will put the value of $\dfrac{1}{{\cos x}} = secx$ in the above equation then we get
$ = \int {({{\sec }^2}x)} dx$
Now we know that we can distribute integration on addition and subtraction so we will integrate it because $\int {({{\sec }^2}x)} dx = \tan x + c$ then
$ = \int {({{\sec }^2}x)} dx$
Now we know that the integration of $\int {{{\sec }^2}} xdx = \tan x$ now we will put these values in above equation then we get
$ = \tan x + c$
Where $c$is the constant value which we get when we do integration of any identity
Therefore the integration of ${(\dfrac{1}{{\cos x}})^2}$ is the $\tan x + c$ which is our required answer.
Note:
We can solve it directly by only using the second conversion formula by just putting the value of $\dfrac{1}{{\cos x}} = secx$ and then we get the same answer in the three or four step, if this question is in the objective type otherwise follow the above method.
As we know about the integral, it is used for finding the areas, volumes and for central points etc. We use it for finding the integration of a particular given identity. It is denoted by the $\int {} $ sign; it is done with respect to a variable which can be $x,y,z$ etc.
Complete step by step solution:
Given that –
According to question integrate ${(\dfrac{1}{{\cos x}})^2}$
Let – $I = {(\dfrac{1}{{\cos x}})^2}$
Now we can write it as ${(\dfrac{1}{{\cos x}})^2} = \dfrac{1}{{{{\cos }^2}x}}$ because both are same in the trigonometry identity
We know that the three basic identity of trigonometry are First is ${\sin ^2}x + {\cos ^2}x = 1$ and second is ${\tan ^2}x + 1 = {\sec ^2}x$ and the third identity is the ${\cot ^2}x + 1 = \cos e{c^2}x$.
We have to know the conversion formula in the trigonometry which are very useful so now we will see them $\dfrac{1}{{\sin x}} = \cos ecx$ and $\dfrac{1}{{\cos x}} = secx$ and $\dfrac{1}{{\tan x}} = \cot x$ now we will use our second formula which is $\dfrac{1}{{\cos x}} = secx$
Now we will integrate the $I$ with respect to $x$
$ = \int I $
$ = \int {\dfrac{1}{{{{\cos }^2}x}}dx} $
Now we will put the value of $\dfrac{1}{{\cos x}} = secx$ in the above equation then we get
$ = \int {({{\sec }^2}x)} dx$
Now we know that we can distribute integration on addition and subtraction so we will integrate it because $\int {({{\sec }^2}x)} dx = \tan x + c$ then
$ = \int {({{\sec }^2}x)} dx$
Now we know that the integration of $\int {{{\sec }^2}} xdx = \tan x$ now we will put these values in above equation then we get
$ = \tan x + c$
Where $c$is the constant value which we get when we do integration of any identity
Therefore the integration of ${(\dfrac{1}{{\cos x}})^2}$ is the $\tan x + c$ which is our required answer.
Note:
We can solve it directly by only using the second conversion formula by just putting the value of $\dfrac{1}{{\cos x}} = secx$ and then we get the same answer in the three or four step, if this question is in the objective type otherwise follow the above method.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

RNA and DNA are chiral molecules their chirality is class 12 chemistry CBSE

