Question

Find the HCF of $40,50$ and $60$.

Answer 1

Hint:The largest or greatest common factor to any two or more given natural numbers is termed as HCF of $40,50\,\,and\,\,60$.So lets make use of this definition and find HCF by any of the suitable methods


Complete step by step solution:

 We have 40,50 and 60
Let us solve it one by one:

$2$	$40$
$2$	$20$
$2$	$10$
$5$	$5$
For 50	$1$
$2$	$50$
$5$	$25$
$5$	$5$
	$1$

$2$	$60$
$2$	$30$
$3$	$15$
$5$	$5$
	$1$

\[40 = 2 \times 2 \times 2 \times 5\;\], $50 = 2 \times 5 \times 5$, $60 = 2 \times 2 \times 3 \times 5$
$40 = {2^3} \times 5$, $50 = 2 \times {5^2}$ $60 = {2^2} \times 3 \times 5$
So, HCF of $40,50,60$ is the least common factor
Then $HCF = 2 \times 5$
$HCF = 10$
Hence, $HCF$ of $40,50$ and $60$ is $10$.

Note: We can also follow an alternate method where we can do prime factorization of numbers and then take common for HCF.