
How do you find the GCF of $10ab$ and $25a$?
Answer
531.3k+ views
Hint: The greatest positive integer that divides equally into all numbers with zero left as the remainder is the greatest common factor (GCF) or the highest common factor (HCF) of a group of whole numbers. There are many ways to find the greatest common factor or the GCF of the numbers.
Here, the terms are in terms of variables. We can use the prime factorisation method here. We write all the prime factors of the given numbers and expand the variables also. Then, we note down the common prime factors in all numbers and then we multiply the common factors to get the highest common factor.
Complete step by step solution:
We have the numbers as $10ab$ and $25a$.
We use the prime factorisation method here to find the greatest common factor of the given numbers.
By the factoring method, we have:
The factorisation of $10ab$ is $10ab = 2 \times 5 \times a \times b$.
The factorisation of $25a$ is $25a = 5 \times 5 \times a$.
Here, we can note down the common factors of $10ab$ and $25a$ which are $5$ and $a$.
So, we multiply the common factors $5$ and $a$ to get the greatest common factor.
Thus, GCF $ = 5 \times a = 5a$
Hence, $5a$ is the GCF of $10ab$ and $25a$
Note: We can also use the factoring method, wherein we write down all the factors (not prime factors like the method above) of the numbers and then we check which of the factors are common and the greatest among those common factors would be GCF or HCF. We should also give more attention when variables are given in exponent form or more than one variable while writing down the factors.
Here, the terms are in terms of variables. We can use the prime factorisation method here. We write all the prime factors of the given numbers and expand the variables also. Then, we note down the common prime factors in all numbers and then we multiply the common factors to get the highest common factor.
Complete step by step solution:
We have the numbers as $10ab$ and $25a$.
We use the prime factorisation method here to find the greatest common factor of the given numbers.
By the factoring method, we have:
The factorisation of $10ab$ is $10ab = 2 \times 5 \times a \times b$.
The factorisation of $25a$ is $25a = 5 \times 5 \times a$.
Here, we can note down the common factors of $10ab$ and $25a$ which are $5$ and $a$.
So, we multiply the common factors $5$ and $a$ to get the greatest common factor.
Thus, GCF $ = 5 \times a = 5a$
Hence, $5a$ is the GCF of $10ab$ and $25a$
Note: We can also use the factoring method, wherein we write down all the factors (not prime factors like the method above) of the numbers and then we check which of the factors are common and the greatest among those common factors would be GCF or HCF. We should also give more attention when variables are given in exponent form or more than one variable while writing down the factors.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

