
How do you find the equation of a line which has x-intercept 2 and y intercept -3?
Answer
555.9k+ views
Hint: We know that the equation of a slope is given by$m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}$. Here $m$represents slope and$\left( {{x_1},{y_1}} \right)$,$\left( {{x_2},{y_2}} \right)$ represent the two points. So first we need to find the slope for which we need to find the points using the given information and substitute it in the equation given above.Also the point slope formula states that $\left( {y - {y_1}} \right) = m\left( {x - {x_1}} \right)$. In this equation we have to substitute the slope that we found and thus find the equation of the line.
Complete step by step answer:
Given,
x intercept: 2 $ \Rightarrow $ x intercept of 2 is the point $\left( {2,0} \right)$
y intercept: -3 $ \Rightarrow $ y intercept of -3 is the point $\left( {0, - 3} \right)$
So here $\left( {{x_1},{y_1}} \right)$ is $\left( {2,0} \right)$and$\left( {{x_2},{y_2}} \right)$ is $\left( {0, - 3} \right)$.Now using the first equation to find the slope of the line such that$m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}$:
\[
\Rightarrow m = \dfrac{{ - 3 - 0}}{{0 - 2}} \\
\Rightarrow m = \dfrac{{ - 3}}{{ - 2}} \\
\Rightarrow m = \dfrac{3}{2}...............\left( i \right) \\ \]
Now on getting$m$, substituting the value of $m$in point slope formula which is $\left( {y - {y_1}} \right) = m\left( {x - {x_1}} \right)$
Also here$\left( {{x_1},{y_1}} \right)$ is$\left( {2,0} \right)$.
$ \Rightarrow \left( {y - 0} \right) = \dfrac{3}{2}\left( {x - 2} \right)...............\left( {ii} \right)$
Solving (ii) to get the equation of line.
\[
\Rightarrow y = \dfrac{3}{2}\left( {x - 2} \right) \\
\Rightarrow y = \dfrac{3}{2}x - \left( {\dfrac{3}{2} \times 2} \right) \\
\therefore y = \dfrac{3}{2}x - 3..................\left( {iii} \right) \\ \]
Therefore the required equation is represented in (iii): \[y = \dfrac{3}{2}x - 3\].
Note:Alternative method: By using slope intercept equation of a line we can directly find the equation of the line.The slope intercept equation of a line is: $y = mx + b$.Here $m$ is the slope and $b$ is the y intercept. So substituting the given values and values in (i) we get:
$
\Rightarrow y = mx + b \\
\Rightarrow y = \dfrac{3}{2}x - 3 \\ $
So by using this method one can directly find the equation using simple substitution.
While doing this type of questions always consider the following points:
-x intercept of \[a\] is the point $\left( {a,0} \right)$.
-y intercept of \[b\] is the point $\left( {0,b} \right)$.
-Point slope formula mainly connects the slope of a line and the point on the line.
Complete step by step answer:
Given,
x intercept: 2 $ \Rightarrow $ x intercept of 2 is the point $\left( {2,0} \right)$
y intercept: -3 $ \Rightarrow $ y intercept of -3 is the point $\left( {0, - 3} \right)$
So here $\left( {{x_1},{y_1}} \right)$ is $\left( {2,0} \right)$and$\left( {{x_2},{y_2}} \right)$ is $\left( {0, - 3} \right)$.Now using the first equation to find the slope of the line such that$m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}$:
\[
\Rightarrow m = \dfrac{{ - 3 - 0}}{{0 - 2}} \\
\Rightarrow m = \dfrac{{ - 3}}{{ - 2}} \\
\Rightarrow m = \dfrac{3}{2}...............\left( i \right) \\ \]
Now on getting$m$, substituting the value of $m$in point slope formula which is $\left( {y - {y_1}} \right) = m\left( {x - {x_1}} \right)$
Also here$\left( {{x_1},{y_1}} \right)$ is$\left( {2,0} \right)$.
$ \Rightarrow \left( {y - 0} \right) = \dfrac{3}{2}\left( {x - 2} \right)...............\left( {ii} \right)$
Solving (ii) to get the equation of line.
\[
\Rightarrow y = \dfrac{3}{2}\left( {x - 2} \right) \\
\Rightarrow y = \dfrac{3}{2}x - \left( {\dfrac{3}{2} \times 2} \right) \\
\therefore y = \dfrac{3}{2}x - 3..................\left( {iii} \right) \\ \]
Therefore the required equation is represented in (iii): \[y = \dfrac{3}{2}x - 3\].
Note:Alternative method: By using slope intercept equation of a line we can directly find the equation of the line.The slope intercept equation of a line is: $y = mx + b$.Here $m$ is the slope and $b$ is the y intercept. So substituting the given values and values in (i) we get:
$
\Rightarrow y = mx + b \\
\Rightarrow y = \dfrac{3}{2}x - 3 \\ $
So by using this method one can directly find the equation using simple substitution.
While doing this type of questions always consider the following points:
-x intercept of \[a\] is the point $\left( {a,0} \right)$.
-y intercept of \[b\] is the point $\left( {0,b} \right)$.
-Point slope formula mainly connects the slope of a line and the point on the line.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

