
How do you find the distance between $\left( 7,2 \right),\left( -5,7 \right)$ ?
Answer
527.4k+ views
Hint: We are asked to find the distance between two given coordinates that lie on the real plane. For this, we use the distance formula. We substitute the values of x – coordinates and the y – coordinates and then evaluate to get the result, which is a positive value, which will be the distance between these two coordinates.
Complete step by step solution:
The given two coordinates are, $\left( 7,2 \right),\left( -5,7 \right)$
We are asked to find the distance between these two points.
For this, we use the distance formula.
First, let us denote some variables for the x – coordinates and the y – coordinates of these points for easy evaluation without confusion.
Let ${{x}_{1}}$ be the x – coordinate of the first point which is 7.
${{x}_{2}}$ will then be the x – coordinate of the second point which is -5.
Let ${{y}_{1}}$ be the x – coordinate of the first point which is 2.
${{y}_{2}}$ will then be the x – coordinate of the second point which is 7.
The distance formula for any two points on the real cartesian plane is given by,
$D=\sqrt{{{\left( {{x}_{2}}-{{x}_{1}} \right)}^{2}}+{{\left( {{y}_{2}}-{{y}_{1}} \right)}^{2}}}$
Now let us substitute the values of the x – coordinates and the y – coordinates of these points.
Upon substitution we get,
$\Rightarrow D=\sqrt{{{\left( -5-7 \right)}^{2}}+{{\left( 7-2 \right)}^{2}}}$
Now evaluate the contents inside the brackets first and then the power on it, according to the BODMAS rule.
$\Rightarrow D=\sqrt{{{\left( -12 \right)}^{2}}+{{\left( 5 \right)}^{2}}}$
Further, evaluate the expression.
$\Rightarrow D=\sqrt{144+25}$
$\Rightarrow D=\sqrt{169}$
Now further simplify the square root.
$\Rightarrow D=13$
Hence, the distance between the points is given by the value, 13.
Note: The formula for finding the distance between any two coordinates $({{x}_{1}},{{y}_{1}}),({{x}_{2}},{{y}_{2}})$ is given by, $d=\sqrt{{{({{x}_{2}}-{{x}_{1}})}^{2}}+{{({{y}_{2}}-{{y}_{1}})}^{2}}}$ . One should always note that the value resulted will never be negative because it is how far is one point from another and it is always positive.
Complete step by step solution:
The given two coordinates are, $\left( 7,2 \right),\left( -5,7 \right)$
We are asked to find the distance between these two points.
For this, we use the distance formula.
First, let us denote some variables for the x – coordinates and the y – coordinates of these points for easy evaluation without confusion.
Let ${{x}_{1}}$ be the x – coordinate of the first point which is 7.
${{x}_{2}}$ will then be the x – coordinate of the second point which is -5.
Let ${{y}_{1}}$ be the x – coordinate of the first point which is 2.
${{y}_{2}}$ will then be the x – coordinate of the second point which is 7.
The distance formula for any two points on the real cartesian plane is given by,
$D=\sqrt{{{\left( {{x}_{2}}-{{x}_{1}} \right)}^{2}}+{{\left( {{y}_{2}}-{{y}_{1}} \right)}^{2}}}$
Now let us substitute the values of the x – coordinates and the y – coordinates of these points.
Upon substitution we get,
$\Rightarrow D=\sqrt{{{\left( -5-7 \right)}^{2}}+{{\left( 7-2 \right)}^{2}}}$
Now evaluate the contents inside the brackets first and then the power on it, according to the BODMAS rule.
$\Rightarrow D=\sqrt{{{\left( -12 \right)}^{2}}+{{\left( 5 \right)}^{2}}}$
Further, evaluate the expression.
$\Rightarrow D=\sqrt{144+25}$
$\Rightarrow D=\sqrt{169}$
Now further simplify the square root.
$\Rightarrow D=13$
Hence, the distance between the points is given by the value, 13.
Note: The formula for finding the distance between any two coordinates $({{x}_{1}},{{y}_{1}}),({{x}_{2}},{{y}_{2}})$ is given by, $d=\sqrt{{{({{x}_{2}}-{{x}_{1}})}^{2}}+{{({{y}_{2}}-{{y}_{1}})}^{2}}}$ . One should always note that the value resulted will never be negative because it is how far is one point from another and it is always positive.
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