
How do you find the distance between $\left( 7,2 \right),\left( -5,7 \right)$ ?
Answer
445.5k+ views
Hint: We are asked to find the distance between two given coordinates that lie on the real plane. For this, we use the distance formula. We substitute the values of x – coordinates and the y – coordinates and then evaluate to get the result, which is a positive value, which will be the distance between these two coordinates.
Complete step by step solution:
The given two coordinates are, $\left( 7,2 \right),\left( -5,7 \right)$
We are asked to find the distance between these two points.
For this, we use the distance formula.
First, let us denote some variables for the x – coordinates and the y – coordinates of these points for easy evaluation without confusion.
Let ${{x}_{1}}$ be the x – coordinate of the first point which is 7.
${{x}_{2}}$ will then be the x – coordinate of the second point which is -5.
Let ${{y}_{1}}$ be the x – coordinate of the first point which is 2.
${{y}_{2}}$ will then be the x – coordinate of the second point which is 7.
The distance formula for any two points on the real cartesian plane is given by,
$D=\sqrt{{{\left( {{x}_{2}}-{{x}_{1}} \right)}^{2}}+{{\left( {{y}_{2}}-{{y}_{1}} \right)}^{2}}}$
Now let us substitute the values of the x – coordinates and the y – coordinates of these points.
Upon substitution we get,
$\Rightarrow D=\sqrt{{{\left( -5-7 \right)}^{2}}+{{\left( 7-2 \right)}^{2}}}$
Now evaluate the contents inside the brackets first and then the power on it, according to the BODMAS rule.
$\Rightarrow D=\sqrt{{{\left( -12 \right)}^{2}}+{{\left( 5 \right)}^{2}}}$
Further, evaluate the expression.
$\Rightarrow D=\sqrt{144+25}$
$\Rightarrow D=\sqrt{169}$
Now further simplify the square root.
$\Rightarrow D=13$
Hence, the distance between the points is given by the value, 13.
Note: The formula for finding the distance between any two coordinates $({{x}_{1}},{{y}_{1}}),({{x}_{2}},{{y}_{2}})$ is given by, $d=\sqrt{{{({{x}_{2}}-{{x}_{1}})}^{2}}+{{({{y}_{2}}-{{y}_{1}})}^{2}}}$ . One should always note that the value resulted will never be negative because it is how far is one point from another and it is always positive.
Complete step by step solution:
The given two coordinates are, $\left( 7,2 \right),\left( -5,7 \right)$
We are asked to find the distance between these two points.
For this, we use the distance formula.
First, let us denote some variables for the x – coordinates and the y – coordinates of these points for easy evaluation without confusion.
Let ${{x}_{1}}$ be the x – coordinate of the first point which is 7.
${{x}_{2}}$ will then be the x – coordinate of the second point which is -5.
Let ${{y}_{1}}$ be the x – coordinate of the first point which is 2.
${{y}_{2}}$ will then be the x – coordinate of the second point which is 7.
The distance formula for any two points on the real cartesian plane is given by,
$D=\sqrt{{{\left( {{x}_{2}}-{{x}_{1}} \right)}^{2}}+{{\left( {{y}_{2}}-{{y}_{1}} \right)}^{2}}}$

Now let us substitute the values of the x – coordinates and the y – coordinates of these points.
Upon substitution we get,
$\Rightarrow D=\sqrt{{{\left( -5-7 \right)}^{2}}+{{\left( 7-2 \right)}^{2}}}$
Now evaluate the contents inside the brackets first and then the power on it, according to the BODMAS rule.
$\Rightarrow D=\sqrt{{{\left( -12 \right)}^{2}}+{{\left( 5 \right)}^{2}}}$
Further, evaluate the expression.
$\Rightarrow D=\sqrt{144+25}$
$\Rightarrow D=\sqrt{169}$
Now further simplify the square root.
$\Rightarrow D=13$
Hence, the distance between the points is given by the value, 13.
Note: The formula for finding the distance between any two coordinates $({{x}_{1}},{{y}_{1}}),({{x}_{2}},{{y}_{2}})$ is given by, $d=\sqrt{{{({{x}_{2}}-{{x}_{1}})}^{2}}+{{({{y}_{2}}-{{y}_{1}})}^{2}}}$ . One should always note that the value resulted will never be negative because it is how far is one point from another and it is always positive.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Trending doubts
State and prove Bernoullis theorem class 11 physics CBSE

Raindrops are spherical because of A Gravitational class 11 physics CBSE

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

Write the differences between monocot plants and dicot class 11 biology CBSE

Why is steel more elastic than rubber class 11 physics CBSE

Explain why a There is no atmosphere on the moon b class 11 physics CBSE
