
Find the difference between total surface area and curved surface area of a hemisphere of radius 21 cm.
A. \[1376c{{m}^{2}}\]
B. \[1386c{{m}^{2}}\]
C. \[1396c{{m}^{2}}\]
D.\[1404c{{m}^{2}}\]
Answer
616.8k+ views
Hint: To solve the question, we have to apply the formula for calculating the total surface area and the curved surface area of the hemisphere for the given radius value of 21 cm. To solve further, we have to subtract the obtained values to calculate the difference between total surface area and curved surface area of the hemisphere of the given radius.
Complete step-by-step answer:
We know that the formula for curved surface area of hemisphere is given by \[2\pi {{r}^{2}}\]
where r is the radius of the hemisphere.
The given value for the radius of the hemisphere is equal to 21 cm.
By substituting the value of radius of the hemisphere in the above-mentioned formula, we get
The curved surface area of hemisphere
\[\begin{align}
& =2\pi {{(21)}^{2}} \\
& =2\pi (441) \\
& =\pi (882) \\
\end{align}\]
We know the value of \[\pi =\dfrac{22}{7}\]. Thus, we get
\[\begin{align}
& =\dfrac{22}{7}\times 882 \\
& =22\times 126 \\
& =2772 \\
\end{align}\]
We know that the formula for total surface area of hemisphere is given by \[3\pi {{r}^{2}}\]
By substituting the value of radius of the hemisphere in the above-mentioned formula, we get
The total surface area of hemisphere
\[\begin{align}
& =3\pi {{(21)}^{2}} \\
& =3\pi (441) \\
& =\pi (1323) \\
\end{align}\]
By substituting the value of \[\pi \], we get
\[\begin{align}
& =\dfrac{22}{7}\times 1323 \\
& =22\times 189 \\
& =4158 \\
\end{align}\]
The difference between total surface area and curved surface area of hemisphere of the given radius
= total surface area of hemisphere - curved surface area of hemisphere
By substituting the above values, we get
= 4158 – 2772
= 1386
The difference between total surface area and curved surface area of hemisphere of the given radius is equal to \[1386c{{m}^{2}}\]
Hence, option (b) is the right choice.
Note: The possibility of mistake can be not applying the appropriate formula for calculating the total surface area and the curved surface area of the hemisphere of the given radius. The other possibility of mistake can be the calculation mistake since it involves large numbers calculation.
Complete step-by-step answer:
We know that the formula for curved surface area of hemisphere is given by \[2\pi {{r}^{2}}\]
where r is the radius of the hemisphere.
The given value for the radius of the hemisphere is equal to 21 cm.
By substituting the value of radius of the hemisphere in the above-mentioned formula, we get
The curved surface area of hemisphere
\[\begin{align}
& =2\pi {{(21)}^{2}} \\
& =2\pi (441) \\
& =\pi (882) \\
\end{align}\]
We know the value of \[\pi =\dfrac{22}{7}\]. Thus, we get
\[\begin{align}
& =\dfrac{22}{7}\times 882 \\
& =22\times 126 \\
& =2772 \\
\end{align}\]
We know that the formula for total surface area of hemisphere is given by \[3\pi {{r}^{2}}\]
By substituting the value of radius of the hemisphere in the above-mentioned formula, we get
The total surface area of hemisphere
\[\begin{align}
& =3\pi {{(21)}^{2}} \\
& =3\pi (441) \\
& =\pi (1323) \\
\end{align}\]
By substituting the value of \[\pi \], we get
\[\begin{align}
& =\dfrac{22}{7}\times 1323 \\
& =22\times 189 \\
& =4158 \\
\end{align}\]
The difference between total surface area and curved surface area of hemisphere of the given radius
= total surface area of hemisphere - curved surface area of hemisphere
By substituting the above values, we get
= 4158 – 2772
= 1386
The difference between total surface area and curved surface area of hemisphere of the given radius is equal to \[1386c{{m}^{2}}\]
Hence, option (b) is the right choice.
Note: The possibility of mistake can be not applying the appropriate formula for calculating the total surface area and the curved surface area of the hemisphere of the given radius. The other possibility of mistake can be the calculation mistake since it involves large numbers calculation.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

