
Find the curve for which the portion of the tangent included between the coordinate axes is bisected at the point of contact is
A.a parabola
B.an ellipse
C.a hyperbola
D.a circle
Answer
569.1k+ views
Hint: Here let us take point $P(x,y)$ as the point of contact of tangent and curve. The slope of tangent is $\dfrac{dy}{dx}$ and using slope-point form we get the equation of tangent. After that find the points at which tangent meet both axes by substituting $x=0$ and then $y=0$. Then take the midpoint and integrate.
Complete step-by-step answer:
Here let us take point $P(x,y)$ as the point of contact of tangent and curve and also slope of tangent is $\dfrac{dy}{dx}$.
The equation of line through $({{x}_{0}},{{y}_{0}})$ and $m$ as slope is $y-{{y}_{0}}=m(x-{{x}_{0}})$.
Now for equation of tangent let us substitute slope and points, we get,
$Y-y=\dfrac{dy}{dx}(X-x)$
Now let us find the coordinates on both the axes, for that let us consider $Y$ intercept, where $X=0$.
$Y-y=\dfrac{dy}{dx}(0-x)$
Now simplifying above we get,
$Y=y-x\dfrac{dy}{dx}$ …………. (1)
So, the point becomes $A\left( 0,y-x\dfrac{dy}{dx} \right)$.
Now, for $X$ intercept, $Y=0$, we get,
$0-y=\dfrac{dy}{dx}(X-x)$
Now simplifying above we get,
$X=x-y\dfrac{dx}{dy}$
So, the point is $B\left( x-y\dfrac{dx}{dy},0 \right)$.
Now in question it is mentioned that it is bisected at point of contact.
So now, taking midpoint we get,
For $x$ axis part,
$x=\dfrac{0+x-y\dfrac{dx}{dy}}{2}$
On simplifying we get,
$x=-y\dfrac{dx}{dy}$
On separating variables we get,
$\dfrac{dy}{y}=-\dfrac{dx}{x}$
No integrating above both sides we get,
$\int{\dfrac{dy}{y}}=-\int{\dfrac{dx}{x}}$
We know that, $\int{\dfrac{1}{a}da=\log a+\log c}$.
So, we get,
$\log y=-\log x+\log c$
Simplifying we get,
$\log y+\log x=\log c$
Now we know that, $\log a+\log b=\log (ab)$
So, using above property we get,
$\log xy=\log c$
Taking antilog on both sides we get,
$xy=c$
Where $c$ is constant.
We can see that it is a curve of rectangular hyperbola.
The curve is hyperbola.
The correct answer is option (C).
Note: A hyperbola is the locus of all those points in a plane such that the difference in their distances from two fixed points in the plane is a constant. Hyperbola is defined as an open curve having two branches which are mirror images to each other. It is two curves that are like infinite bows. In other words, the locus of a point moving in a plane in such a way that the ratio of its distance from a fixed point (focus) to that from a fixed line (directrix) is a constant greater than 1.
Complete step-by-step answer:
Here let us take point $P(x,y)$ as the point of contact of tangent and curve and also slope of tangent is $\dfrac{dy}{dx}$.
The equation of line through $({{x}_{0}},{{y}_{0}})$ and $m$ as slope is $y-{{y}_{0}}=m(x-{{x}_{0}})$.
Now for equation of tangent let us substitute slope and points, we get,
$Y-y=\dfrac{dy}{dx}(X-x)$
Now let us find the coordinates on both the axes, for that let us consider $Y$ intercept, where $X=0$.
$Y-y=\dfrac{dy}{dx}(0-x)$
Now simplifying above we get,
$Y=y-x\dfrac{dy}{dx}$ …………. (1)
So, the point becomes $A\left( 0,y-x\dfrac{dy}{dx} \right)$.
Now, for $X$ intercept, $Y=0$, we get,
$0-y=\dfrac{dy}{dx}(X-x)$
Now simplifying above we get,
$X=x-y\dfrac{dx}{dy}$
So, the point is $B\left( x-y\dfrac{dx}{dy},0 \right)$.
Now in question it is mentioned that it is bisected at point of contact.
So now, taking midpoint we get,
For $x$ axis part,
$x=\dfrac{0+x-y\dfrac{dx}{dy}}{2}$
On simplifying we get,
$x=-y\dfrac{dx}{dy}$
On separating variables we get,
$\dfrac{dy}{y}=-\dfrac{dx}{x}$
No integrating above both sides we get,
$\int{\dfrac{dy}{y}}=-\int{\dfrac{dx}{x}}$
We know that, $\int{\dfrac{1}{a}da=\log a+\log c}$.
So, we get,
$\log y=-\log x+\log c$
Simplifying we get,
$\log y+\log x=\log c$
Now we know that, $\log a+\log b=\log (ab)$
So, using above property we get,
$\log xy=\log c$
Taking antilog on both sides we get,
$xy=c$
Where $c$ is constant.
We can see that it is a curve of rectangular hyperbola.
The curve is hyperbola.
The correct answer is option (C).
Note: A hyperbola is the locus of all those points in a plane such that the difference in their distances from two fixed points in the plane is a constant. Hyperbola is defined as an open curve having two branches which are mirror images to each other. It is two curves that are like infinite bows. In other words, the locus of a point moving in a plane in such a way that the ratio of its distance from a fixed point (focus) to that from a fixed line (directrix) is a constant greater than 1.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

