Find the coordinates of the points of trisection of the line segment joining the points $\left( { - 3,3} \right)$ and $\left( {3, - 3} \right)$.
Answer
626.4k+ views
Hint: Make a line segment (let’s say AB) with two points names (let’s say P and Q) on it. Mark the points A and B with the coordinates given in the question. Apply the section formula internally i.e. $\left( {\dfrac{{l{x_2} + m{x_1}}}{{l + m}},\dfrac{{l{y_2} + m{y_1}}}{{l + m}}} \right)$.
Complete step-by-step answer:
Now, when we look at the ratio at which each point divides the line AB internally, we see that it's 1:2 on point P and 2:1 on point Q.
Thus, P divides the line AB internally in the ratio 1:2
Q divides the line AB internally in the ratio 2:1
Writing the section formula internally we have, $\left( {\dfrac{{l{x_2} + m{x_1}}}{{l + m}},\dfrac{{l{y_2} + m{y_1}}}{{l + m}}} \right)$.
Now, as we have already discussed, P divides the line segment AB in the ratio 1:2 so,
$l = 1,m = 2$
And,
$
\left( {{x_1},{y_1}} \right) = \left( { - 3,3} \right) \\
\\
\left( {{x_2},{y_2}} \right) = \left( {3, - 3} \right) \\
$
So, after putting in the values we have till now and the values which were given in the questions we have,
$
\to \left( {\dfrac{{1 \times 3 + 2 \times - 3}}{{1 + 2}},\dfrac{{1 \times - 3 + 2 \times 3}}{{1 + 2}}} \right) \\
\\
\to \left( {\dfrac{{3 - 6}}{3},\dfrac{{ - 3 + 6}}{3}} \right) \\
\\
\to \left( { - 1,1} \right) \\
$
Since we know that Q divides the line segment AB in the ratio 2:1 so.
$l = 2,m = 1$
And,
$
\left( {{x_1},{y_1}} \right) = \left( { - 3,3} \right) \\
\\
\left( {{x_2},{y_2}} \right) = \left( {3, - 3} \right) \\
$
After putting the values again, we have-
$
\to \left( {\dfrac{{2 \times 3 + 1 \times - 3}}{{2 + 1}},\dfrac{{2 \times - 3 + 1 \times 3}}{{2 + 1}}} \right) \\
\\
\to \left( {\dfrac{{6 - 3}}{3},\dfrac{{ - 6 + 3}}{3}} \right) \\
\\
\to \left( {1, - 1} \right) \\
$
Thus, after evaluating both the points through section formula internally, we now have the coordinates of the points P and Q i.e.-
$ \to P\left( { - 1,1} \right),Q\left( {1, - 1} \right)$
Note: Whenever asked to find out the coordinates of the point of intersection on any line segment, always apply the section formula and put the values of the coordinates given in the question. Read the coordinates carefully and do not miss the signs of the coordinates for it may vary your answer.
Complete step-by-step answer:
Now, when we look at the ratio at which each point divides the line AB internally, we see that it's 1:2 on point P and 2:1 on point Q.
Thus, P divides the line AB internally in the ratio 1:2
Q divides the line AB internally in the ratio 2:1
Writing the section formula internally we have, $\left( {\dfrac{{l{x_2} + m{x_1}}}{{l + m}},\dfrac{{l{y_2} + m{y_1}}}{{l + m}}} \right)$.
Now, as we have already discussed, P divides the line segment AB in the ratio 1:2 so,
$l = 1,m = 2$
And,
$
\left( {{x_1},{y_1}} \right) = \left( { - 3,3} \right) \\
\\
\left( {{x_2},{y_2}} \right) = \left( {3, - 3} \right) \\
$
So, after putting in the values we have till now and the values which were given in the questions we have,
$
\to \left( {\dfrac{{1 \times 3 + 2 \times - 3}}{{1 + 2}},\dfrac{{1 \times - 3 + 2 \times 3}}{{1 + 2}}} \right) \\
\\
\to \left( {\dfrac{{3 - 6}}{3},\dfrac{{ - 3 + 6}}{3}} \right) \\
\\
\to \left( { - 1,1} \right) \\
$
Since we know that Q divides the line segment AB in the ratio 2:1 so.
$l = 2,m = 1$
And,
$
\left( {{x_1},{y_1}} \right) = \left( { - 3,3} \right) \\
\\
\left( {{x_2},{y_2}} \right) = \left( {3, - 3} \right) \\
$
After putting the values again, we have-
$
\to \left( {\dfrac{{2 \times 3 + 1 \times - 3}}{{2 + 1}},\dfrac{{2 \times - 3 + 1 \times 3}}{{2 + 1}}} \right) \\
\\
\to \left( {\dfrac{{6 - 3}}{3},\dfrac{{ - 6 + 3}}{3}} \right) \\
\\
\to \left( {1, - 1} \right) \\
$
Thus, after evaluating both the points through section formula internally, we now have the coordinates of the points P and Q i.e.-
$ \to P\left( { - 1,1} \right),Q\left( {1, - 1} \right)$
Note: Whenever asked to find out the coordinates of the point of intersection on any line segment, always apply the section formula and put the values of the coordinates given in the question. Read the coordinates carefully and do not miss the signs of the coordinates for it may vary your answer.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

The largest wind power cluster is located in the state class 11 social science CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Which among the following are examples of coming together class 11 social science CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

