
Find the class mark of the class $35 - 40$
Answer
495.3k+ views
Hint: Since given that the class mark in two different types, like the highest mark can be obtained is given as $40$ and then the lowest mark can be obtained is given as $35$ with these two given class marks we need to find the average mark of the class, hence we will make use of the average formula that sum of the given numbers divided by the total numbers count.
Complete step-by-step solution:
Since given that class mark of the class $35 - 40$. We can clearly see that the upper limit value is $40$ because which is the greater value and then the lower limit value is given as $35$ because this is the lesser value. Hence the average formula or also called as the midpoint of the two numbers formula is $\dfrac{{40 + 35}}{2}$ means $CM = \dfrac{{UL + LL}}{2}$ where CM is the class mark, UL is the upper limit given, and also LL is the lower limit given.
Hence further solving we get $CM = \dfrac{{40 + 35}}{2} \Rightarrow \dfrac{{75}}{2}$ using the addition operation.
Therefore, we have $CM = \dfrac{{75}}{2} \Rightarrow 37.5$ using the division operation.
Hence, we get the average class mark as $37.5$
Note: The inverse of multiplication method is called division. Like $x \times y = z$is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $CM = \dfrac{{75}}{2} \Rightarrow 37.5$. Making use of the upper and lower limits on the class count and using simple operations, we solved the given problem. Sometimes students make mistakes by assuming the class mark as mean, which is not true, class mark is the mid value for the given interval.
Complete step-by-step solution:
Since given that class mark of the class $35 - 40$. We can clearly see that the upper limit value is $40$ because which is the greater value and then the lower limit value is given as $35$ because this is the lesser value. Hence the average formula or also called as the midpoint of the two numbers formula is $\dfrac{{40 + 35}}{2}$ means $CM = \dfrac{{UL + LL}}{2}$ where CM is the class mark, UL is the upper limit given, and also LL is the lower limit given.
Hence further solving we get $CM = \dfrac{{40 + 35}}{2} \Rightarrow \dfrac{{75}}{2}$ using the addition operation.
Therefore, we have $CM = \dfrac{{75}}{2} \Rightarrow 37.5$ using the division operation.
Hence, we get the average class mark as $37.5$
Note: The inverse of multiplication method is called division. Like $x \times y = z$is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $CM = \dfrac{{75}}{2} \Rightarrow 37.5$. Making use of the upper and lower limits on the class count and using simple operations, we solved the given problem. Sometimes students make mistakes by assuming the class mark as mean, which is not true, class mark is the mid value for the given interval.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

