
How do you find the area of the rectangle is square meters, having the length 1.4 m and width is 2.9 m?
Answer
539.1k+ views
Hint: The product of length and width is called the area of the rectangle. By putting the values of length and width in the formula of area of a rectangle and we will get the answer for the area of a rectangle. The unit of area is always in the square units.
Complete step by step solution:
The region covered by the rectangle in the two – dimensional plane is known as the area of the rectangle. There are four sides and four vertices in the rectangle which are two – dimensional shapes. All the four angles of the rectangle are right angles. We can recognize the rectangle by its property of having the opposite sides parallel and equal to each other and angles are also equal to each other.
The perimeter of the rectangle is the sum of all four sides of the rectangle. As there are four sides and opposite sides are equal to each other. Therefore, the formula for the perimeter of a rectangle is –
$P = 2\left( {l + w} \right)$
where $l$ is the length of the rectangle and $w$ is the width of the rectangle.
The area of the rectangle is the product of the length and width of the rectangle. It is always expressed in square units. Therefore, in mathematical expression, it can be expressed as –
$A = l \times w$
where $l$ is the length of the rectangle and $w$ is the width of the rectangle.
According to the question, it is given that –
Length of rectangle, $l = 1.4m$
Width of rectangle, $w = 2.9m$
Putting the values of length and width of the rectangle in the formula of area of a rectangle, we get –
$
\Rightarrow A = 1.4 \times 2.9 \\
\Rightarrow A = 4.06{m^2} \\
$
Hence, the required area of the rectangle is $4.06{m^2}$
Note:
We can also solve this question by using the formula of area of rectangle by diagonal –
$Area = Width\sqrt {\left[ {{{\left( {Diagonal} \right)}^2} - {{\left( {Width} \right)}^2}} \right]} $ or $Area = Length\sqrt {\left[ {{{\left( {Diagonal} \right)}^2} - {{\left( {Length} \right)}^2}} \right]} $
For finding the value of diagonal we can use the formula –
${\left( {Diagonal} \right)^2} = {\left( {Length} \right)^2} + {\left( {Width} \right)^2}$.
Complete step by step solution:
The region covered by the rectangle in the two – dimensional plane is known as the area of the rectangle. There are four sides and four vertices in the rectangle which are two – dimensional shapes. All the four angles of the rectangle are right angles. We can recognize the rectangle by its property of having the opposite sides parallel and equal to each other and angles are also equal to each other.
The perimeter of the rectangle is the sum of all four sides of the rectangle. As there are four sides and opposite sides are equal to each other. Therefore, the formula for the perimeter of a rectangle is –
$P = 2\left( {l + w} \right)$
where $l$ is the length of the rectangle and $w$ is the width of the rectangle.
The area of the rectangle is the product of the length and width of the rectangle. It is always expressed in square units. Therefore, in mathematical expression, it can be expressed as –
$A = l \times w$
where $l$ is the length of the rectangle and $w$ is the width of the rectangle.
According to the question, it is given that –
Length of rectangle, $l = 1.4m$
Width of rectangle, $w = 2.9m$
Putting the values of length and width of the rectangle in the formula of area of a rectangle, we get –
$
\Rightarrow A = 1.4 \times 2.9 \\
\Rightarrow A = 4.06{m^2} \\
$
Hence, the required area of the rectangle is $4.06{m^2}$
Note:
We can also solve this question by using the formula of area of rectangle by diagonal –
$Area = Width\sqrt {\left[ {{{\left( {Diagonal} \right)}^2} - {{\left( {Width} \right)}^2}} \right]} $ or $Area = Length\sqrt {\left[ {{{\left( {Diagonal} \right)}^2} - {{\left( {Length} \right)}^2}} \right]} $
For finding the value of diagonal we can use the formula –
${\left( {Diagonal} \right)^2} = {\left( {Length} \right)^2} + {\left( {Width} \right)^2}$.
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