Find the area of a trapezium whose parallel sides are \[24cm\] and \[20cm\] the distance between them is \[15cm\].
Answer
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Hint: A convex quadrilateral with at least one pair of parallels side is referred to as a trapezium in English outside America but as a trapezoid. The parallel sides are called the bases of the trapezoid and the other two.
Sides are called the legs or lateral sides. A scalene trapezoid or trapezoid with no sides of equal measure. A right trapezoid has two adjacent right angles; right trapezoids are used in the trapezoid rule for estimating areas under a curve.
A paralleled is a trapezoid with two pairs of parallel sides. A parallelogram has two pairs of parallel sides. A parallelogram has 2-fold rotational symmetry/ it is possible for obtuse trapezoids or right trapezoids.
Complete step by step answer:
We know
Area of trapezoid \[ = \dfrac{1}{2} \times \] sum of parallel sides \[ \times \]distance between two
Area of trapezium \[\dfrac{1}{2}(a + b)\]
Where a and b are base 4h is height
Here \[a = 24cm\,,b = 20cm,\,h = 15cm\]
Area \[ = \dfrac{{15}}{2}(24 + 20) = 330c{m^2}\]
Area of trapeziums with distance of \[15cm\] between parallel sides is \[330c{m^2}\].
Note:
This can also be done using a line perpendicular from one of the parallel lines and then dividing trapezium into a triangle and a parallelogram and then finding an area triangle and parallelogram and then summing.
Sides are called the legs or lateral sides. A scalene trapezoid or trapezoid with no sides of equal measure. A right trapezoid has two adjacent right angles; right trapezoids are used in the trapezoid rule for estimating areas under a curve.
A paralleled is a trapezoid with two pairs of parallel sides. A parallelogram has two pairs of parallel sides. A parallelogram has 2-fold rotational symmetry/ it is possible for obtuse trapezoids or right trapezoids.
Complete step by step answer:
We know
Area of trapezoid \[ = \dfrac{1}{2} \times \] sum of parallel sides \[ \times \]distance between two
Area of trapezium \[\dfrac{1}{2}(a + b)\]
Where a and b are base 4h is height
Here \[a = 24cm\,,b = 20cm,\,h = 15cm\]
Area \[ = \dfrac{{15}}{2}(24 + 20) = 330c{m^2}\]
Area of trapeziums with distance of \[15cm\] between parallel sides is \[330c{m^2}\].
Note:
This can also be done using a line perpendicular from one of the parallel lines and then dividing trapezium into a triangle and a parallelogram and then finding an area triangle and parallelogram and then summing.
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