Question

Find the area of a rhombus whose diagonals are of length 4cm and 1.5cm.

Answer 1

Hint: We know that ,
Area of rhombus \[ = \dfrac{{d_1 \times d_2}}{2}\] square unit using this concept we will approach to question . First find measure of d then put it in this formula to find the solution.

Complete step-by-step answer:
Given
Diagonal $d_1$ \[ = 4\] cm
Diagonal $d_2$ \[ = 1.5\] cm
Area of rhombus \[ = \dfrac{{d_1 \times d_2}}{2}\] square units.
Area \[ = \dfrac{{4 \times 1.5}}{2}\] $cm^2$
Area \[ = 3.0\] $cm^2$

So the area of the rhombus is $3$ $cm^2$

Additional Information: A Rhombus is a flat shape quadrilateral whose four sides all have the same length. With equal straight sides a rhombus looks like a diamond. All sides have equal length and also its other name is equilateral quadrilateral. Opposite angles are equal (it is a parallelogram). The altitude is the distance at right angle to two sides.
Properties of rhombus: -
1 Opposite angle of rhombus is equal.
2. The diagonals of the rhombus are perpendicular to each other, hence, rhombus is an orthodiagonal quadrilateral.

d1 and d2 are two diagonals of rhombus.
The opposite angle of a rhombus is equal to another. Also, the diagonals of a rhombus bisect the angles.
Area of rhombus can be calculated by
Area of rhombus \[ = \dfrac{{d_1 \times d_2}}{2}\] square unit.
Where
$d_1$ & $d_2$ are diagonals.
Perimeter of rhombus \[ = 4a\] units
a \[ = \] side

Note: We can also find the area of rhombus when base and height are given.
Area of rhombus \[ = \] B \[ \times \] H
Where B \[ = \] length of any side.
             H \[ = \] height of rhombus.