
Find the area of a regular pentagon whose each side is $8$ cm long and the radius of whose circumscribed circle is $7$ cm.
Answer
569.7k+ views
Hint: Use the formula of area of pentagon when circumscribed circle is given-
Area of pentagon= $\dfrac{{\text{n}}}{{\text{2}}} \times {{a \times }}\sqrt {{{\text{R}}^{\text{2}}}{\text{ - }}\dfrac{{{{\text{a}}^{\text{2}}}}}{{\text{4}}}} $ where n is the number of sides of the polygon, R is the radius of circumscribed triangle and ‘a’ is the length of the each side of polygon. Now we know that the Pentagon has five sides. A regular pentagon has equal five sides so put n=$5$ . Then by putting the given values in the formula and simplifying, get the area of the pentagon.
Complete step-by-step answer:
Given, the length of each side of regular pentagon=$8$ cm
The radius of the circumscribed circle =$7$ cm
We know the formula of area of pentagon which circumscribed circle is given as-
Area of pentagon= $\dfrac{{\text{n}}}{{\text{2}}} \times {{a \times }}\sqrt {{{\text{R}}^{\text{2}}}{\text{ - }}\dfrac{{{{\text{a}}^{\text{2}}}}}{{\text{4}}}} $ where n is the number of sides of the polygon, R is the radius of circumscribed triangle and ‘a’ is the length of the each side of polygon.
Since the polygon is pentagon so n=$5$, a=$8$ cm and R=$7$ cm
On putting these values in the formula we get,
Area of pentagon=$\dfrac{5}{{\text{2}}} \times 8{{ \times }}\sqrt {{7^{\text{2}}}{\text{ - }}\dfrac{{{8^{\text{2}}}}}{{\text{4}}}} $
On solving we get,
Area of pentagon=$5 \times 4{{ \times }}\sqrt {{\text{49 - }}\dfrac{{64}}{{\text{4}}}} $
On simplifying we get,
Area of pentagon=$20{{ \times }}\sqrt {{\text{49 - }}16} $
On subtraction we get,
Area of pentagon=$20\sqrt {33} $
On further simplifying we get,
Then area of pentagon=$20 \times 5.74$
On multiplication we get,
Area of pentagon=$114.8$ ${\text{c}}{{\text{m}}^2}$.
Note: The properties of pentagon are as follows-
The sum of all interior angles in the pentagon is equal to ${540^\circ }$ .
If all sides and angles are equal to each other it is a regular polygon.
In a regular pentagon the interior angle is equal to ${108^\circ }$ and exterior angle is equal to ${72^\circ }$.
Area of pentagon= $\dfrac{{\text{n}}}{{\text{2}}} \times {{a \times }}\sqrt {{{\text{R}}^{\text{2}}}{\text{ - }}\dfrac{{{{\text{a}}^{\text{2}}}}}{{\text{4}}}} $ where n is the number of sides of the polygon, R is the radius of circumscribed triangle and ‘a’ is the length of the each side of polygon. Now we know that the Pentagon has five sides. A regular pentagon has equal five sides so put n=$5$ . Then by putting the given values in the formula and simplifying, get the area of the pentagon.
Complete step-by-step answer:
Given, the length of each side of regular pentagon=$8$ cm
The radius of the circumscribed circle =$7$ cm
We know the formula of area of pentagon which circumscribed circle is given as-
Area of pentagon= $\dfrac{{\text{n}}}{{\text{2}}} \times {{a \times }}\sqrt {{{\text{R}}^{\text{2}}}{\text{ - }}\dfrac{{{{\text{a}}^{\text{2}}}}}{{\text{4}}}} $ where n is the number of sides of the polygon, R is the radius of circumscribed triangle and ‘a’ is the length of the each side of polygon.
Since the polygon is pentagon so n=$5$, a=$8$ cm and R=$7$ cm
On putting these values in the formula we get,
Area of pentagon=$\dfrac{5}{{\text{2}}} \times 8{{ \times }}\sqrt {{7^{\text{2}}}{\text{ - }}\dfrac{{{8^{\text{2}}}}}{{\text{4}}}} $
On solving we get,
Area of pentagon=$5 \times 4{{ \times }}\sqrt {{\text{49 - }}\dfrac{{64}}{{\text{4}}}} $
On simplifying we get,
Area of pentagon=$20{{ \times }}\sqrt {{\text{49 - }}16} $
On subtraction we get,
Area of pentagon=$20\sqrt {33} $
On further simplifying we get,
Then area of pentagon=$20 \times 5.74$
On multiplication we get,
Area of pentagon=$114.8$ ${\text{c}}{{\text{m}}^2}$.
Note: The properties of pentagon are as follows-
The sum of all interior angles in the pentagon is equal to ${540^\circ }$ .
If all sides and angles are equal to each other it is a regular polygon.
In a regular pentagon the interior angle is equal to ${108^\circ }$ and exterior angle is equal to ${72^\circ }$.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Which places in India experience sunrise first and class 9 social science CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Write the 6 fundamental rights of India and explain in detail

Difference Between Plant Cell and Animal Cell

What is pollution? How many types of pollution? Define it

What is the full form of pH?

