
Find the area of a circle with diameter \[6\] unit.
Answer
556.8k+ views
Hint: The diameter of the circle is given, from there we can find the radius as the diameter is twice the radius and hence with the radius the area can be found.
Complete step by step solution:
Let the area of the circle be represented by \[A\].
Let the diameter of the circle be represented by \[D\].
Let the radius of the circle be represented by \[R\].
First, find out the radius of the circle:
Given diameter \[ = \] \[6\] unit.
Diameter of a circle is twice its radius,
\[\therefore \] radius \[\left( R \right)\] \[ = \] \[\dfrac{D}{2}\] (where \[D\] ids the diameter of the circle.)
\[ \Rightarrow \] \[R\] \[ = \] \[\dfrac{6}{2}\] unit
\[ \Rightarrow \] \[R\] \[ = \] \[3\] unit
The area of a circle is given by the formula:
\[A = \pi {R^2}\] ; \[\left[ {\pi = \dfrac{{22}}{7}} \right]\]
Substitute the value of \[R\] in the formula for the area:
\[A = \pi {R^2}\]
\[ \Rightarrow \] \[A = \pi {\left( 6 \right)^2}\] square unit.
\[ \Rightarrow \] \[A = \pi \left( {6 \times 6} \right)\] square unit.
\[ \Rightarrow \] \[A = 36\pi \] square unit.
Substitute value of \[\pi \]:
\[ \Rightarrow \] \[A = 36 \times \left( {\dfrac{{22}}{7}} \right)\] square unit.
\[ \Rightarrow \] \[A = \dfrac{{792}}{7}\] square unit.
Hence, the area of the circle is \[\dfrac{{792}}{7}\] square unit.
Note: Observe the question carefully whether the radius or the diameter is given. The formula stated is applicable for the radius only, so if the diameter is given then convert it to the radius and don’t substitute directly in the formula.
\[\pi \] is a constant defined as the ratio of the circumference of a circle to the diameter of the circle. Its value is equal to \[\dfrac{{22}}{7}\] or \[3.14\](approximately).
Complete step by step solution:
Let the area of the circle be represented by \[A\].
Let the diameter of the circle be represented by \[D\].
Let the radius of the circle be represented by \[R\].
First, find out the radius of the circle:
Given diameter \[ = \] \[6\] unit.
Diameter of a circle is twice its radius,
\[\therefore \] radius \[\left( R \right)\] \[ = \] \[\dfrac{D}{2}\] (where \[D\] ids the diameter of the circle.)
\[ \Rightarrow \] \[R\] \[ = \] \[\dfrac{6}{2}\] unit
\[ \Rightarrow \] \[R\] \[ = \] \[3\] unit
The area of a circle is given by the formula:
\[A = \pi {R^2}\] ; \[\left[ {\pi = \dfrac{{22}}{7}} \right]\]
Substitute the value of \[R\] in the formula for the area:
\[A = \pi {R^2}\]
\[ \Rightarrow \] \[A = \pi {\left( 6 \right)^2}\] square unit.
\[ \Rightarrow \] \[A = \pi \left( {6 \times 6} \right)\] square unit.
\[ \Rightarrow \] \[A = 36\pi \] square unit.
Substitute value of \[\pi \]:
\[ \Rightarrow \] \[A = 36 \times \left( {\dfrac{{22}}{7}} \right)\] square unit.
\[ \Rightarrow \] \[A = \dfrac{{792}}{7}\] square unit.
Hence, the area of the circle is \[\dfrac{{792}}{7}\] square unit.
Note: Observe the question carefully whether the radius or the diameter is given. The formula stated is applicable for the radius only, so if the diameter is given then convert it to the radius and don’t substitute directly in the formula.
\[\pi \] is a constant defined as the ratio of the circumference of a circle to the diameter of the circle. Its value is equal to \[\dfrac{{22}}{7}\] or \[3.14\](approximately).
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Difference Between Plant Cell and Animal Cell

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Which places in India experience sunrise first and class 9 social science CBSE

What is pollution? How many types of pollution? Define it

Name 10 Living and Non living things class 9 biology CBSE

What is the full form of pH?

