Question

Find the area and the perimeter of a rectangular plot of land whose length and breadth are 28.5 m and 20 m respectively.

Answer 1

Hint – In this particular type of question use the concept that the area of the rectangular plot is the multiplication of the length and breadth of the rectangle and perimeter of any shape is the sum of all the side lengths of the shape so use these concepts to reach the solution of the question.

Complete step-by-step answer:

Given data:
Length and breadth of the rectangular plot are 28.5 meter and 20 meter respectively.
Let the length be denoted by L and the breadth be denoted by B.
So, L = 28.5 meter
And, B = 20 meter.
The pictorial representation of the rectangular plot is shown in the above diagram.
Now as we know that in a rectangle the opposite sides are equal to each other.
So the length of the opposite side of the rectangle is also 28.5 meter and the breadth of the opposite side of the rectangle is also 20 meter as shown in the figure.
Now as we know that the perimeter of any shape is the sum of all the side lengths of the shape.
So the perimeter of the rectangle is the sum of all the sides of the rectangle.
Let perimeter be denoted by P.
Therefore, P = 2(L + B) = 2(28.5 + 20) = 2(48.5) = 97 meter.
So the perimeter of the rectangle is 97 meter.
Now as we know that the area (A) of the rectangle is the product of the length and the breadth of the rectangle.
So the area of the rectangle is
A = length $ \times $ Breadth.
Now substitute the values we have,
Therefore, A = 28.5 $ \times $ 20 = 570 square meter.
So this is the required answer.

Note – Whenever we face such types of questions the key concept we have to remember is that in the rectangle opposite sides are equal so mark the opposite sides of the rectangle then calculate the perimeter of the rectangle by adding all the sides and calculate the area of rectangle by multiplying length and breadth and simplify we will get the required answer.