Answer
Verified
406.2k+ views
Hint: Here the principal amount is Rs.36000 and we are given that it is compounded annually with a rate of interest of 10% for first year and 12% for second year and using this the amount at the end of two years is given by the formula $A = P\left( {1 + \dfrac{{{R_1}}}{{100}}} \right)\left( {1 + \dfrac{{{R_2}}}{{100}}} \right)$.
Complete step by step solution:
We are given a principle amount
$ \Rightarrow P = 36000$
And we are given that it was compounded annually
And we are given two different rate of interests for each year
So now let the rate of interest for first year be ${R_1}$
$ \Rightarrow {R_1} = 10\% $
And the rate of interest for second year be ${R_2}$
$ \Rightarrow {R_2} = 12\% $
Therefore the amount at the end of 2 years will be
$ \Rightarrow A = P\left( {1 + \dfrac{{{R_1}}}{{100}}} \right)\left( {1 + \dfrac{{{R_2}}}{{100}}} \right)$
Now let's use the known values in this formula
\[
\Rightarrow A = 36000\left( {1 + \dfrac{{10}}{{100}}} \right)\left( {1 + \dfrac{{12}}{{100}}} \right) \\
\Rightarrow A = 36000\left( {1 + \dfrac{1}{{10}}} \right)\left( {1 + \dfrac{3}{{25}}} \right) \\
\Rightarrow A = 36000\left( {\dfrac{{10 + 1}}{{10}}} \right)\left( {\dfrac{{25 + 3}}{{25}}} \right) \\
\Rightarrow A = 36000\left( {\dfrac{{11}}{{10}}} \right)\left( {\dfrac{{28}}{{25}}} \right) \\
\Rightarrow A = 36000\left( {\dfrac{{308}}{{250}}} \right) = 3600\left( {\dfrac{{308}}{{25}}} \right) \\
\Rightarrow A = 144\times 308 = 44352 \\
\]
Therefore the amount at the end of two years is Rs.44352.
Note :
Students may tend to use the formula of compound interest
$ \Rightarrow A = P{\left( {1 + \dfrac{R}{{100}}} \right)^t}$
But we don’t use this here because we are given different rates of interest for each year.
Compound interest makes your money grow faster because interest is calculated on the accumulated interest over time as well as on your original principal.
Compound interest is the interest calculated on the principal and the interest accumulated over the previous period. It is different from the simple interest where interest is not added to the principal while calculating the interest during the next period. Compound interest finds its usage in most of the transactions in the banking and finance sectors and also in other areas as well.
Complete step by step solution:
We are given a principle amount
$ \Rightarrow P = 36000$
And we are given that it was compounded annually
And we are given two different rate of interests for each year
So now let the rate of interest for first year be ${R_1}$
$ \Rightarrow {R_1} = 10\% $
And the rate of interest for second year be ${R_2}$
$ \Rightarrow {R_2} = 12\% $
Therefore the amount at the end of 2 years will be
$ \Rightarrow A = P\left( {1 + \dfrac{{{R_1}}}{{100}}} \right)\left( {1 + \dfrac{{{R_2}}}{{100}}} \right)$
Now let's use the known values in this formula
\[
\Rightarrow A = 36000\left( {1 + \dfrac{{10}}{{100}}} \right)\left( {1 + \dfrac{{12}}{{100}}} \right) \\
\Rightarrow A = 36000\left( {1 + \dfrac{1}{{10}}} \right)\left( {1 + \dfrac{3}{{25}}} \right) \\
\Rightarrow A = 36000\left( {\dfrac{{10 + 1}}{{10}}} \right)\left( {\dfrac{{25 + 3}}{{25}}} \right) \\
\Rightarrow A = 36000\left( {\dfrac{{11}}{{10}}} \right)\left( {\dfrac{{28}}{{25}}} \right) \\
\Rightarrow A = 36000\left( {\dfrac{{308}}{{250}}} \right) = 3600\left( {\dfrac{{308}}{{25}}} \right) \\
\Rightarrow A = 144\times 308 = 44352 \\
\]
Therefore the amount at the end of two years is Rs.44352.
Note :
Students may tend to use the formula of compound interest
$ \Rightarrow A = P{\left( {1 + \dfrac{R}{{100}}} \right)^t}$
But we don’t use this here because we are given different rates of interest for each year.
Compound interest makes your money grow faster because interest is calculated on the accumulated interest over time as well as on your original principal.
Compound interest is the interest calculated on the principal and the interest accumulated over the previous period. It is different from the simple interest where interest is not added to the principal while calculating the interest during the next period. Compound interest finds its usage in most of the transactions in the banking and finance sectors and also in other areas as well.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
At which age domestication of animals started A Neolithic class 11 social science CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
One cusec is equal to how many liters class 8 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Change the following sentences into negative and interrogative class 10 english CBSE